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frosja888 [35]
3 years ago
14

Henry has two pixie sticks full of delicious sugar. Henry

Mathematics
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

14.67 gram

Step-by-step explanation:

Henry has two pixie sticks full of delicious sugar.

Now, each pixie stick contains 22 grams of sugary goodness, then in two sticks, there will be (22 × 2) = 44 grams of sugar.

Now, Henry shares two pixie sticks among two friends and himself in equal proportion.  

Therefore, each of his friends will get \frac{44}{3} = 14.67 (Round to the nearest tenth) gram of sugary goodness. (Answer)

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Gala2k [10]
18-4x=7x+7
(subtract 7 from both sides)
11-4x=7x
(Add 4x to both sides)
11=11x
(divide both sides by 11)
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8 0
3 years ago
An orchard has 651 orange trees. The number of rows exceeds the number of trees per row by 10. How many trees are there in a row
natima [27]

Answer:

The number of trees in each row is  21.

Step-by-step explanation:

Let us assume the number of trees in each row  = m

So, the number of rows in the orchard = Number of trees in each row + 10

or, total number of trees in each row = (10 +m)

Now, Total number of Trees = Number of Rows x Number of trees in 1 row

⇒ 651  = m (m + 10)

651 = m^2 + 10m\\\implies  m^2 + 10m - 651 =0\\or,   m^2 + 31m  21m - 651 =0\\or, m(m +31) -21(m+31) =0\\\implies (m +31) (m-21) = 0

⇒ (m +31) = 0, or (m-21) = 0

⇒ m= -31, or m = 21

Now, as m = The number of trees in each row, so m ≠ -31

So, m =  21

Hence, the number of trees in each row is m = 21.

8 0
4 years ago
Swim team members can race or dive. At a meet, 18 members race. The ratio of racers to divers is 6:2. How many meters are on the
kirza4 [7]

Answer:

6 meters

Step-by-step explanation:

Set up a proportion as 18/x=6/2. The meters are unknown, so that's what the x value represents. Then, cross multiply (18 times 2 and 6 times x) to get 36=6x. By dividing both sides of the equation by 6, you'll get 6 meters as your answer.

HAVE A GREAT DAY!!! :D

8 0
3 years ago
Read 2 more answers
The sum of the first 10 terms of an AP is four times the sum of the first 5 terms then the ratio of the first term to the common
Mashcka [7]

Answer:

The ratio of the first term to the common difference is 1 : 2

Step-by-step explanation:

The rule of the sum of the AP is

S_{n}=\frac{n}{2}[2a+(n-1)d] , where

a is the first number

d is the common difference

n is the position of the number

∵ S_{10} = 4 × S_{5} ⇒ (1)

→ Find S_{10}  and S_{5}

∵ In S_{10} n = 10

∴ S_{10}=\frac{10}{2}[2a+(10-1)d]

∴ S_{10}=5[2a+9d]

∴ S_{10} = 10a + 45d ⇒ (2)

∵ In S_{5} n = 5

∴ S_{5}=\frac{5}{2}[2a+(5-1)d]

∴ S_{5}=2.5[2a+4d]

∴ S_{5} = 5a + 10d ⇒ (3)

→ Substitute (2) and (3) in (1)

∵ 10a + 45d = 4[5a + 10d]

∴ 10a +45d = 20a + 40d

→ Subtract 40d from both sides

∴ 10a + 45d - 40d = 20a + 40d - 40d

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→ Subtract 10a from both sides

∴ 10a - 10a + 5d = 20a - 10a

∴ 5d = 10a

→ Divide both sides by 5

∴ d = 2a

→ That means d is twice a or a is half d

∴ a : d = 1 : 2

The ratio of the first term to the common difference is 1 : 2

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