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3 years ago

Graph a line with a slope of -3 that contains the point (4, -2)

Mathematics

1 answer:

Crank3 years ago

5 0

Answer:

Step-by-step explanation:

Given that

Slope m=-3

A point (x, y)=(4,-2)

Equation of a line can generally be written as

y=mx+c

Where, m is the slope

And c is the intercept on y-axis

Since we are given m=-3

Then, y=mx+c becomes

y=-3x+c

To get c, let substitute the point given, i.e x=4 and y=-2

y=-3x+c

-2=-3(4)+c

-2=-12+c

-2+12=c

c=-2+12

c=10

y=mx+c, then m=-3 and c=10

Then, the equation the line becomes y = -3x + 10

This is the required line equation

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3 years ago

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3 years ago

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Starting with the first question: 9x + 2y = 6

Firstly, subtract 9x on both sides: 2y = -9x + 6

Next, divide both sides by 2, and your equation will be y = -4.5x + 3

Now with the next equation: y - 3 = 4(x + 1)

Firstly, foil 4(x + 1): y - 3 = 4x + 4

Next, subtract y on both sides: -3 = 4x - y + 4

Next, subtract 4 on both sides, and your answer will be: -7 = 4x - y

Next equation: y + 7 = -2(x - 3)

Firstly, foil -2(x - 3): y + 7 = -2x + 6

Next, subtract 7 on both sides of the equation, and your answer will be: y = -2x - 1

Next: y - 5 = 3(x - 2) (part a)

Firstly, foil 3(x - 2): y - 5 = 3x - 6

Next, add 5 on both sides, and your equation is: y = 3x - 1

Next, y - 5 = 3(x - 2) (part b)

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4 0

3 years ago

If you use the addition property of equality , what number would you add to both sides of the equal sign to isolate the variable

kkurt [141]

Answer:

The answer is " $\frac{26}{7}$ "

Step-by-step explanation:

The whole question can be found in the file attached.

$\to x + \frac{5}{7} = \frac{31}{7}\\\\$

Subtracting the $\frac{5}{7}$ from both sides of the equations:

$\to x +\frac{5}{7} - \frac{5}{7} = \frac{31}{7} - \frac{5}{7} \\\\$

$= \frac{31-5}{7} \\\\= \frac{26}{7} \\\\$

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3 years ago