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3 years ago

Graph a line with a slope of -3 that contains the point (4, -2)

Mathematics

1 answer:

Crank3 years ago

5 0

Answer:

Step-by-step explanation:

Given that

Slope m=-3

A point (x, y)=(4,-2)

Equation of a line can generally be written as

y=mx+c

Where, m is the slope

And c is the intercept on y-axis

Since we are given m=-3

Then, y=mx+c becomes

y=-3x+c

To get c, let substitute the point given, i.e x=4 and y=-2

y=-3x+c

-2=-3(4)+c

-2=-12+c

-2+12=c

c=-2+12

c=10

y=mx+c, then m=-3 and c=10

Then, the equation the line becomes y = -3x + 10

This is the required line equation

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Can I have help solving for x?:))

zvonat [6]

Answer:

24.8

Step-by-step explanation:

We will have to use trigonometry here to find the value of x. The first thing we can see is that we need to work out the hypotenuse. We need to chose whether to use Sin, Cos or Tan. We do that by look at the sides .

→ 'x' is the hypotenuse

→ 12 is opposite

→ The adjacent is the side that doesn't have a numerical value to we look for a formula triangle without adjacent in it

Tan = Opposite ÷ Adjacent

Sin = Opposite ÷ Hypotenuse

Cos = Adjacent ÷ Hypotenuse

We can see the Sin formula has no adjacent in it so we use that formula. However we want to work out the hypotenuse so we have to rearrange the sin formula to get hypotenuse as the subject so

Sin = Opposite ÷ Hypotenuse

Hypotenuse = Opposite ÷ Sin

→ Let's substitute in the values

Hypotenuse = 12 ÷ Sin(29)

Hypotenuse = 24.7519841

So the value of x is 24.8 to 1 decimal place

6 0

3 years ago

Read 2 more answers

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago

A(n) ____________ chart compares data from three columns and/or rows in a three-dimensional manner

9966 [12]

A(n) is a special type of hyphen that prevents two words separated by a hyphen from splitting at the end of a line.

7 0

3 years ago

Identify the 33rd term of the arithmetic sequence 9, 7 and one half, 6...

marta [7]

Answer:

-39

Step-by-step explanation:

The general term of an arithmetic sequence is ...

an = a1 +d(n -1)

This sequence has first term a1=9 and common difference d=(7.5-9) = -1.5. Then the 33rd term is ...

a33 = 9 -1.5(33 -1) = 9 -48 = -39

The 33rd term is -39.

5 0

3 years ago

Pls help asap

VMariaS [17]

Answer: Addition

Step-by-step explanation: You can represent that as 10^5*10^-5

If you add the exponent values, you get 10^0 which is equal to 1. If you multiply them, you get 10^-25 which is wrong.

3 0

2 years ago

Read 2 more answers