$\left \{ {{a - 3b = 16} \atop {a = b - 2}} \right. \\ \\ \left \{ {{a = 16 + 3b} \atop { 16 + 3b = b - 2}} \right. \\ \\ \left \{ {{a = 16 + 3b} \atop {3b - b = - 2 - 16}} \right. \\ \\ \left \{ {{a =16 + 3b} \atop {2b = -18}} \right. \\ \\ \left \{ {{a=16 + 3b} \atop {b=-9}} \right. \\ \\ \left \{ {{a=16 + 3b = 16 + 3*(-9) = 16 - 27 = -11} \atop {b=-9}} \right.$

Answer a = -11, b = -9

8 0

3 years ago

PLZ PLZ HELP ME. THANKYOU. WILL GIVE BRAINLIEST

Alex Ar [27]

1. One solution
2.one solution
3.no solution
4.one solution
Hope this helped!

6 0

3 years ago

Solve n³ + 2n² - 15n = 0 by factoring. Show the factored form of the equation, and the resulting solutions.

laila [671]

Step-by-step explanation:

Take n common

n(n²+2n-15)=0

now factorise the quadratic one as n when goes to RHS it becomes zero

n²-3n+5n-15=0

n(n-3)+5(n-3)=0

n=3,-5

4 0

3 years ago

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