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2 years ago

Which equation demonstrates the additive identity property?

Mathematics

1 answer:

kramer2 years ago

6 0

It's the first one (7+4i)+(7-4i)=14

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Please help with number 3!! I can’t figure it out.

FrozenT [24]

Answer:

Gabe worked 65, Abe worked 62 and Babe worked 69.

Step-by-step explanation:

Let Gabe = x

Therefore, Abe worked: x-3 and Babe worked x+4

So,

x+(x-3)+(x+4)=196

3*x+1=196

3*x=195

x=65

Then,

x-3= 62

x+4=69

8 0

2 years ago

PLEASE HELP!!! ILL GIVE BRAINLIEST, EXPLAIN YOUR ANSWER PLEASE

mart [117]

Answer: -20v^3 - 30x^2 +20

Step-by-step explanation:

simply multiply each term inside of the parentheses by -5.

4 0

3 years ago

Read 2 more answers

MULTIPLE CHOICE PLEASE HELP UWU

vodka [1.7K]

B)40 because (4)*50/5 is (4)*10

7 0

3 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the <em>area </em>of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

3 years ago

Can anyone help me with this question

Lina20 [59]

Answer:

$78$

idont know

5 0

2 years ago