PSEUDOCODE:
1. DECLARE number: INTEGER
2. DECLARE multiple: INTEGER
3. INPUT number
4. FOR counter FROM 1 TO 10 DO
5. multiple <-- number * counter
6. PRINT number, " * ", counter, " = ", multiple
7. ENDFOR
<em>1. declaring a variable "number" as an Integer</em>
<em>2. declaring a variable "multiple" as an Integer</em>
<em>3. The user inputs the value of number</em>
<em>4. FOR loop where variable "counter" increments by 1 after every iteration</em>
<em>5. sets the value for variable "multiple" as the value of number * counter</em>
<em>6. prints out for example "3 * 1 = 3" and will continue till counter reaches 10</em>
<em>7. Ends the for loop</em>
FLOWCHART below
hope it helped
Answer:
plotter:
A device used to print large maps, drawing, graphs etc is known as plotter. A plotter contains a printing head and a drum through which the paper comes out.Posters can be made by any printing method ie: serigraph, stone lithograph, offset lithograph, woodblock, silk screen on any number of types of paper. A poster is a "publicity" for something.
I am definitely sure that the answer should be: When using powershell, an administrator can use the Install-ADDSForest cmdlet to create a new dc in a new forest. Install-ADDSForest is used to install first domain controller in new forest. To do that, you should execute this command through the command promt. It looks like this: <span>C:\> Install-AddsForest. Then you'll need to set up the attributes.</span>
Answer:
The solution code is written in Python
d = 1.5 + random.random() * 6
Explanation:
By presuming the Python random module is imported, we can use the <em>random</em> method to generate a random number. <em>random.random()</em> will give us a value in the range [0, 1). The ensure the lower limit is 1.5 instead of 0, we can add 1.5 to random.random()
This expression will give any value in range [1.5, 2.5)
To ensure the upper limit is set to 7.5, we tweak the previous expression to
- 1.5 + random.random() * 6
This expression will always multiply a random number from [0,1) with 6 and then only added with 1.5. This will always produce a random number that fulfill the inequality 1.5 ≤ d < 7.5
