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Vikentia [17]
3 years ago
8

What expressions will initialize d with a random value such that all possible values for d are given by the inequality 1.5 ≤ d &

lt; 7.5?
Computers and Technology
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

The solution code is written in Python

d = 1.5 + random.random() * 6

Explanation:

By presuming the Python random module is imported, we can use the <em>random</em> method to generate a random number.  <em>random.random()</em> will give us a value in the range [0, 1). The ensure the lower limit is 1.5 instead of 0, we can add 1.5 to random.random()

  •      1.5 + random.random()

This expression will give any value in range [1.5, 2.5)

To ensure the upper limit is set to 7.5, we tweak the previous expression to

  • 1.5 + random.random() * 6  

This expression will always multiply a random number from [0,1) with 6 and then only added with 1.5. This will always produce a random number that fulfill the inequality 1.5 ≤ d < 7.5

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Answer:

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Explanation:

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5 0
3 years ago
We introduced Sudoku as a CSP to be solved by search over
klemol [59]

Answer:

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8 0
3 years ago
Write a program to prepare the monthly charge account statement for a customer of CS CARD International, a credit card company.
WITCHER [35]

Answer:

import java.util.*;

import java.text.*;

class CreditCardBill

{

public static void main(String[] args)

{

Scanner sc = new Scanner(System.in);

NumberFormat defaultFormat = NumberFormat.getCurrencyInstance(Locale.US);

System.out.println("CS Card International Statement");

System.out.println("===============================");

System.out.print("Previous Balance: $");

double prevBalance = sc.nextDouble();

System.out.print("Additional Charges: $");

double addCharges = sc.nextDouble();

double interest;

if(prevBalance == 0)

interest = 0;

else

interest = (prevBalance + addCharges) * 0.02;

System.out.println("Interest: "+defaultFormat.format(interest));

double newBalance = prevBalance + addCharges + interest;

System.out.println("New Balance: "+defaultFormat.format(newBalance));

double minPayment;

if(newBalance < 50)

minPayment = newBalance;

else if(newBalance <= 300)

minPayment = 50.00;

else

minPayment = newBalance * 0.2;

System.out.println("Minimum Payment: "+defaultFormat.format(minPayment));

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}

5 0
3 years ago
Create a structure representing a student. The member variables should include student name, student ID, and four test grades fo
Neporo4naja [7]

Answer:

Output:

Name: Brainly

ID:0001

Write the 4 tests grades of the student separated by space :10 9 8 10

Brainly

0001

10 9 8 10

Average :9.66667

'1' to continue '0' to exit :

Explanation:

#include<iostream>

#include<string>

using namespace std;

//variables declaration

struct Student {

  string id; //string declaration ID

  string name; // string declaration name

  int grades[4]; //array of 4 because it is 4 grades

};

//definition of the function get information

void inputData(Student &s){

 

   

   cout << "Name:" ;

   getline(cin,s.name);

   cout << "ID:";

   cin >> s.id;

   cout << "Write the 4 tests grades of the student separated by space :";

   for (int i = 0; i<4; i++)

       cin >> s.grades[i];

}

//definition of the function of average

double inputAvg(Student s){

   double summation;

   int temporary;

   double average;

   for (int i = 0; i<4; i++){  

      for (int j = i; j<4; j++){

         if (s.grades[j] > s.grades[i]){

             temporary = s.grades[i];

             s.grades[i] = s.grades[j];

             s.grades[j] = temporary;

         }

      }

    }

    summation = 0;

    for (int i = 0; i<3; i++){

        summation = summation + s.grades[i];  

    }

    average = summation/3;

    return average;

}

void disp(Student *s){

   cout << s->name << endl;

   cout << s->id << endl;

   for (int i = 0; i<4; i++)

       cout << s->grades[i] << " ";

   cout << endl;

   cout << "Average :" << inputAvg(*s) << endl;

   

}

int main(){

  Student st;

  int ch;

  while(true){

      inputData(st);

      disp(&st);

      cout << " '1' to continue '0' to exit :";

      cin >> ch;

      if (ch == 0)

         break;      

  }

  return 0;

}

6 0
3 years ago
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