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Helga [31]
4 years ago
6

Finding Higher-Order Derivatives In Exercise, find the second derivative of the function.

Mathematics
1 answer:
77julia77 [94]4 years ago
8 0

Answer:

Step-by-step explanation:

Given is a function in f as

f(x) = log_{10}  x

We can change base to e for our convenience for finding derivatives

f(x) = log_{e}  x ( log_{10}  e)

The second term is a constant with value = 0.434294

So f(x) = 0.434294 ln x

Now differentiate with respect to x two times

I derivative = f'(x)  = \frac{0.434294}{x} \\f"(x) = - \frac{0.434294}{x^2}

Note: We can leave as log e to base 10 also without converting into actual values.

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–4.36 − 1.6g + 7.4 = 0.3g + 6.46
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Answer:

g = 10.82

_______ or 5.694736842105263

-1.9

Step-by-step explanation:

- 1.6g - 0.3g = 6.46 + 4.36

-1.9g = 10.82

g = 10.82

_____

-1.9

5 0
3 years ago
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3 years ago
In relation t a functions? Is the inverse of relation t function
frozen [14]

Answer:

Relation t is a function. The inverse of relation t is not a function ⇒ 3rd

Step-by-step explanation:

* Lets explain how to solve the problem

- A relation is a set of inputs and outputs, and a function is a relation

 with one output for each input

- Ex: T = {(1 , 2) , (3 , 5) , (-4 , 0)} is a function because every input has

  only one output

- To find the inverse of a function we switched the input and the

  out put

- The inverse of a function may not always be a function

* Lets solve the problem

∵ The relation t is the set of ordered pairs of x and y

  x = 0     2      4    6

  y = -8    -7    -4    -4

∵ x = 0 has only y = -8

∵ x = 2 has only y = -7

∵ x = 4 has only y = -4

∵ x = 6 has only y = -4

∴ Every value of x has only one value of y

∴ Relation t is a function

* Lets find its inverse by switching x and y

∵ The inverse function of t is :

   x = -8     -7     -4    -4

   y =  0      2      4     6

∵ x = -8 has only y = 0

∵ x = -7 has only y = 2

∵ x = -4 has y = 4 and y = 6

∴ Not every value of x has only one value of y

∴ The inverse of relation t is not a function

* Relation t is a function. The inverse of relation t is not a function

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avanturin [10]
2.. expecting something else ?
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3 years ago
Read 2 more answers
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