A building casts a shadow that is 15 meters in length The distance from the top of the building to the top of the shadow is 25 m
1 answer:
Answer:
20 meters
Step-by-step explanation:
The shadow of the building will look like a right triangle. In this problem, the hypotenuse of the triangle is 25 meters, and one of the sides is 15 meters. What we are trying to find is the length of the other side.
We can do this by using pythagoreans theorem.
So, the last side (or the height of the building) is 20 meters.
You might be interested in
Problem 1
Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.
Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.
With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.
Refer to the diagram below.
=====================================================
Problem 2
I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.
In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.
Hi there! The answer is n = 10.
As you see at the powers of x, we need to add the exponents of the power we when multiply them.
The powers of y work the same way.
Hence, n = 10, since
As you see at the powers of x, we need to add the exponents of the power we when multiply them.
The powers of y work the same way.
Hence, n = 10, since