It could be any fraction really. Some examples are 5/6, 7/9 or 12/24. It doesn’t really matter what the fraction ks
Answer:
282°
Step-by-step explanation:
The measure of long arc KLM can be found by first determining the measure of short arc KM. That arc can be found using the inscribed angle theorem.
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<h3>value of x</h3>
The inscribed angle theorem tells you the measure of arc KM is twice the measure of the inscribed angle KLM that subtends it. This relation can be used to find the value of x, hence the measure of the arc.
2∠KLM = arc KM
2(5x -1) = 8x +14
10x -2 = 8x +14 . . . . . . eliminate parentheses
2x = 16 . . . . . . . . . . add 2-8x
x = 8 . . . . . . . . . divide by 2
<h3>measure of arc KM</h3>
The expression for the measure of arc KM can be evaluated.
arc KM = 8x +14 = 8(8) +14 = 78°
<h3>
measure of arc KLM</h3>
The total of arcs of a circle is 360°, so the measure of long arc KLM will bring the total with arc KM to 360°:
arc KM +arc KLM = 360°
arc KLM = 360° -arc KM
arc KLM = 360° -78° = 282°
The measure are long arc KLM is 282°.
Number of child tickets bought is 20
<h3><u>
Solution:</u></h3>
Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket
cost of each child ticket = 5 dollars
cost of each adult ticket = 8 dollars
Let "c" be the number of child tickets bought
Let "a" be the number of adult tickets bought
Total tickets sold were 110 bringing in 820 dollars
<em>Number of child tickets bought + number of adult tickets bought = 110</em>
c + a = 110 ----- eqn 1
<em><u>Also we can frame a equation as:</u></em>
Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820
5c + 8a = 820 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
From eqn 1,
a = 110 - c ------ eqn 3
Substitute eqn 3 in eqn 2
5c + 8(110 - c) = 820
5c + 880 - 8c = 820
-3c = - 60
c = 20
Therefore from eqn 3,
a = 110 - 20 = 90
a = 90
Therefore number of child tickets bought is 20
Answer:
10√2
Step-by-step explanation:
A(1, 4), B(3, 6), C(6, 3), D(4, 1)
The distance formula tells you the distance d between two points (x1, y1) and (x2, y2) is given by ...
d = √((x2-x1)² +(y2-y1)²
Then the side lengths are ...
AB = √(2² +2²) = √8 = 2√2
BC = √(3² +(-3)²) = √18 = 3√2
The perimeter is twice the sum of these sides, so is ...
P = 2(2√2 +3√2) = 10√2 . . . the perimeter of the rectangle
