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Katarina [22]
3 years ago
10

The production rate of a steel factory is declining due to old machinery. Over the last eight days production has dropped by 1.2

tons. What is the average rate of change in steel production over the eight days? Express the answer in tons per day.
Mathematics
2 answers:
Marysya12 [62]3 years ago
6 0
Find the unit rate:

-1.2 tons
------------- = -0.15 ton/day, or -3/20 ton/day
 8 days
erica [24]3 years ago
5 0

Answer:

The average rate of change in steel production over the eight days is 0.15 tons per day

Step-by-step explanation:

Over the last eight days production has dropped by 1.2 tons.

Production dropped in 8 days = - 1.2

Production dropped in 1 day = \frac{-1.2}{8}

                                             = -0.15

So, the average rate of change in steel production over the eight days is 0.15 tons per day

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Answer:

We conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

Step-by-step explanation:

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A FLOC  evaluation of 25 Mexican family units reveals a mean to be $30,000 with a sample standard deviation of $10,000.

Let \mu = <em><u>true mean family income for Mexican migrants.</u></em>

So, Null Hypothesis, H_0 : \mu = $27,000     {means that the mean family income for Mexican migrants to the United States is $27,000 per year}

Alternate Hypothesis, H_A : \mu \neq $27,000     {means that the mean family income for Mexican migrants to the United States is different from $27,000 per year}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

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So, <u><em>the test statistics</em></u>  =  \frac{30,000-27,000}{\frac{10,000}{\sqrt{25} } }  ~ t_2_4

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The value of t test statistics is 1.50.

Since, in the question we are not given the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -2.064 and 2.064 at 24 degree of freedom for two-tailed test.</u>

Since our test statistic lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

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