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3 years ago

To place controls on a form in a stacked layout, select all the controls and click the stacked button on the ____ tab.

1 answer:

3 0

To place controls on a form in a stacked layout, select all the controls and click the stacked button on the Arrange tab. The Arrange tab is located in the C1ReportDesigner's Ribbon menu and provides shortcuts to the Edit, Auto Format, Grid, Control Alignment, Position, and Size menu functions.

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Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type

sattari [20]

Solution :

#include $$$$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal $\text{To}$ Binary(char* hexdec)

{

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$ (sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

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3 years ago

What are the advantage of an e-library

Semmy [17]

Answer:

Makes it easier to read... summarize cite electronic versions of editions

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1 year ago

Can you help please ill give branilist

konstantin123 [22]

HTML uses tags to help the computer know what different pieces of content in the web page actually are. Right now we've only learned how to tell the computer that some text is a paragraph, or that part of your website is the body. We've already seen how that affects the way our web pages look and are structured.

(I don't know how it should be organized, but hope this helped)

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3 years ago

7+9 help me pleas i dont know help now

natali 33 [55]

Answer:

Explanation:

because it is

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2 years ago

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