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3 years ago

Which linear regression equation best fits the given points? (0,8), (1,6), (1,7), (2,4), (2,5), (4,1), (5,1), (6,0)

Mathematics

1 answer:

irina1246 [14]3 years ago

3 0

C. is the answer thank you

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Are the expressions -0.5(3x + 5) and<br> -1.5x + 2.5 equivalent? Explain why or why not.

Sedbober [7]

Answer:

No, because the first equation equals -1.5x + 2.5 when simplified, but when the second equation is simplified it equals 1

7 0

3 years ago

If a 4 x 16 rectangle has the same area as a square, what is the length of a side of the square?

Licemer1 [7]

Answer:

Option D. 8 units

Step-by-step explanation:

step 1

Find the area of rectangle

The area of rectangle is

$A=(4)(16)=64\ units^2$

step 2

Find the length side of the square with the same area of rectangle

The area of a square is

$A=b^2$

where

b is the length side of the square

we have

$A=64\ units^2$

substitute

$64=b^2$

take the square root both sides

$b=8\ units$

therefore

The length side of the square is 8 units

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3 years ago

If a production line produces 50 mouse traps every 30 minutes over the course of a 10 hour work day with a half-hour break for l

kaheart [24]

The factory made 950 mousetraps

7 0

3 years ago

What is A- 3.5= 14.9

gladu [14]

A = 14.9 +3.5 = 18.4 :D

7 0

3 years ago

The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili

Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

$\lambda= 4.5$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

a) No accidents occur in one week.

$P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111$

b) 5 or more accidents occur in a week.

$P( x \geq 5) = 1-\displaystyle \sum P(x$

c) One accident occurs today.

The mean number of accidents per day is given by

$\lambda = \dfrac{4.5}{7} = 0.64$

$P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747$

5 0

3 years ago