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aleksklad [387]
4 years ago
11

Make a box-and-whisker plot for the data. What is the upper quartile value? 56 32 48 52 51 53 48 38 35 42 40 46 54 50

Mathematics
2 answers:
Alika [10]4 years ago
7 0
From the figure the upper quartile is 51.75

timofeeve [1]4 years ago
4 0

Answer:

Step-by-step explanation:

The given data is:

56 32 48 52 51 53 48 38 35 42 40 46 54 50

In order to get the value of the upper quartile, first arrange he given data in ascending form, we get

32, 35, 38, 40, 42, 46, 48, 48, 50, 52, 53, 54, 56

The upper quartile is:48, 50, 52, 53, 54, 56

The value of upper quartile is given as:

\frac{52+53}{2}

=\frac{105}{2}

=52.5

Thus, the value of the upper quartile will be 52.5.

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Write the equation of the line parallel to 3x-y=7 that passes through point (-5, -3)
IceJOKER [234]
<h2>Answer:</h2>

\boxed{y=3x+12}

<h2>Step-by-step explanation:</h2>

In this problem we know the equation of a line, which is:

3x-y=7

We also can write this equation as:

y=3x-7

This line has a slope m=3 which is also the slope of the line we are looking for because they're parallel. We also have a point (-5,-3). Therefore, we can write this equation as follows:

y-y_{0}=m(x-x_{0}) \\ \\ y-(-3)=3(x-(-5)) \\ \\ y+3=3(x+5) \\ \\ y+3=3x+15 \\ \\ \boxed{y=3x+12}

From the figures below, the line in red is 3x-y=7 while the line in blue is y=3x+12 and this line passes through the point (-5, -3)!

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Step-by-step explanation:

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Step-by-step explanation:

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