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LUCKY_DIMON [66]
3 years ago
9

If y=-12, when x=9, find y when x=-4

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0
2 different things
if it is
xy=k or if it is x/y=k
direct or inverse variation

I will do the x/y=k one
9/-12=-3/4
x=-4
-3/4=-4/y
mutiply both sides by y
-3/4y=-4
mutiply both sides by -4/3 to clear fraction
y=16/3




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Step-by-step explanation:

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2 years ago
Angle ABC is a straight angle. m∠DBC = 130° and BE bisects ∠ABD.<br><br><br> What is mEBA?
seraphim [82]
The answer:

we observe that <span>m∠DBC = 130° 
</span><span>
we should find the value of </span>mEDB to answer this question
Angle ABC is a straight angle, so m ABC= 180°, but 
mABD  + <span>m∠DBC = 180° (look at the figure)
</span>
so mABD= 180° - m∠DBC = 180 - 130 = 50°

therefore, mABD= 50°,
and BE bisects ∠ABD imiplies  mEBA = mEDB, and mABD=  mEBA + mEDB= 50°, it does mean 2x mEBA = 50°

and from where mEBA = 50°/2=25°
5 0
3 years ago
Read 2 more answers
How do you solve an inequality like this/<br><br> x-2/x+16 ≥ 0
neonofarm [45]

\bf \cfrac{x-2}{x+16}\ge 0\implies \stackrel{cross-multiplying}{x-2\ge (x+16)0}\implies x-2\ge 0\implies x\ge 2

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3 years ago
Stan guessed on all 10 questions of a multiple-choice quiz. Each question has 4 answer choices. What is the probability that he
algol13

ANSWER
0.756

EXPLANATION

Let x represent number of correct answers.

We can find

   P(x = 0 \text{ or } x = 1)

which leads us to

   P(x\ge 2) = 1 - P(x = 0\text{ or }x = 1)

which uses the compliment of P(x = 0\text{ or }x = 1) to find the probability of getting at least 2 questions correct.

Note that since P(x=0) and P(x=1) are mutually exclusive, we have

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Then P(x=0) = 3^{10}/4^{10} = (3/4)^{10} as we have 3^{10} to answer the questions incorrectly divided by the total 4^{10} to answer the questions.

Exactly 1 answer correct: P(x=1) = {}_{10}C_1 \cdot(3/4)^9(1/4)^1

Therefore

   \begin{aligned}&#10;P(x \ge 2) &= 1 - P(x = 0\text{ or }x =1) \\&#10;&=1 - \big[P(x=0) + P(x=1)\big] \\&#10;&=1 - \left[ (3/4)^{10} + {}_{10}C_1 \cdot (3/4)^9(1/4)^1 \right] \\&#10;&\approx 0.756&#10;\end{aligned}

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Step-by-step explanation:

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