Find two positive numbers who sum is S and the product is a maximum

Mathematics

1 answer:

zalisa [80]3 years ago

5 0

I find this question insufficient. Please be more specific. Imo every positive integer would fulfil your statement.

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Whats the answer 5h-8=2h+19 equality

djyliett [7]

Answer:

Step-by-step explanation:

5h-8=2h+19

5h-2h=19+8

3h=27

h=27/3

h=9

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2 years ago

Plz help me I just started 8th grade.

weeeeeb [17]

Answer:

I think this is slope. So for each point you go up 3 units. All of the point should connect into a straight line.

Step-by-step explanation:

Mark Point R on the graph to its coordniates. Do the same to Point D, L and F. after you are done then go back to each point and go up 3 units/points. Then draw a line connecting the 4 points. Then you will have your answer. Hope this helped!

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2 years ago

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A swimming pool has to be drained for maintenance. The pool is shaped like a cylinder with a diameter of 10 m and a depth of 1.7

love history [14]

About ten days or so

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2 years ago

How much interest will $1,200 earn over 10 years with 5% interest compounded annually

Amiraneli [1.4K]

Answer:

$1,954

Step-by-step explanation:

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2 years ago

25 POINTS AND BRAINLIEST PLEASE HELP ASAP

dexar [7]

M is a midpoint of BC so:

$M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)$

Length of MA:

$MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

Length of NB:

$NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

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3 years ago

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