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olga55 [171]
3 years ago
14

PART ONE: For this assignment, create an html page that has a login form. The form should have 3 input elements -- 1. type text

for the user to enter username 2. type password (like text except cannot see the text that is typed in), for the user to enter password. 3. Submit button (type submit, as we did in class). The button should have the word Login displayed.
Computers and Technology
1 answer:
Digiron [165]3 years ago
3 0

Answer:

The following code are in HTML language:

Login_page.html :

<!DOCTYPE html>

<html lang="en">

<head>

<title>Login_Form</title>

<meta charset="UTF-8">

<meta name="viewport" content="width=device-width, initial-scale=1">

<link href="css/style.css" rel="stylesheet">

</head>

<body>

<form action="Login_page.php" method="post">

<table>

<tr>

<td>UserName</td>

<td>

<input type="text" name="username" placeholder="Username"/>

</td>

</tr>

<tr>

<td>Password</td>

<td>

<input type="password" name="password" placeholder="Password"/>

</td>

</tr>

<tr>

<td>

<input type="Submit" name="login" value="submit"/>

</td>

</tr>

</table>

</form>

</body>

</html>  

Explanation:

Here, we have to use the HTML tag, and HEAD tag and the TITLE tag for the title of the page.

Then, we have to create a table for the structure of Form page by using table tag.  

Then, we have to create form by using Form tag

Then, create two text boxes for the username and the password with the use of an input tag.

Then, we have to create a submit button for submitting the following details with the use of an input tag.

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What will be the value of x after the following code is executed? int x = 10; do { x *= 20; } while (x &lt; 5); A. 10 B. 200 C.
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Answer:

Option B is the correct answer.

Explanation:

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  • Then the statement "x*=20;" will execute one and gives the result 200 for x variable because this statement means "x=x*20".
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5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
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Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

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void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

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Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

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