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Anuta_ua [19.1K]
3 years ago
14

Write an expression that executes the loop body as long as the user enters a non-negative number. Note: If the submitted code ha

s an infinite loop, the system will stop running the code after a few seconds and report "Program end never reached." The system doesn't print the test case that caused the reported message.
Computers and Technology
1 answer:
madam [21]3 years ago
3 0

Answer:

           while (Num>=0) {

               System.out.println("enter a another number");

               Num = in.nextInt();

           }

Explanation:

The complete java code prompting a user to enter a number until a negative number is entered is given below:

import java.util.Scanner;

public class num6 {

public static void main (String [] args) {

Scanner in = new Scanner(System.in);

System.out.println("enter a number");

int Num = in.nextInt();

while (Num>=0) {

System.out.println("enter a another number");

Num = in.nextInt();

}

System.out.println("Done.");

return;

}

}

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A. CAD

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In mathematics, the notation n! represents the factorial of the nonnegative integer n. The factorial of n is the product of all
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Answer:

The program to this question can be given as:

Program:

factorial=1 #declare a variable.  

number=int(input("Enter a positive integer:")) #input a number.  

while (number>0): #loop  

   factorial= factorial*number # holding value in factorial variable  

   number=number-1  

print('=',factorial) #print value.

Output:

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= 720  

Explanation:

The description of the above python program can be given as:

  • In the above program firstly we define a variable that is "factorial". In this variable, we assign a value that is 1 and it is used to calculate the factorial value.  
  • We define a variable "number". The number variable is used to take input from the user.  
  • Then we define a loop in the loop we calculate the factorial and hold the value in the factorial value in the last we print the value.  

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