Step-by-step explanation:
C=4x+3y Constraints: x is greater than or equal to 0 2x + 3y is greater than or equal to 6 3x - 2y is less than or equal to 9 x + 5y is less than or equal to 20
we have
Complete the square. Remember to balance the equation by adding the same constants to each side
Rewrite as perfect squares
therefore
the answer is
We are given the expression of square root of one over 121 and is asked to simplify the expression. Simply, to answer this question, we take the square root of each number. square root of 1 is 1 while the square root of 121 is 11. Hence the simplified expression becomes 1/11.
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
Answer:
Rs166.67
Step-by-step explanation:
Let
x -----> amount of money Arun has in his pocket at the beginning
we know that
100%-25%=75%
75%=75/100=0.75
so
The linear equation that represent this situation is
0.75x=125
Solve for x
Divide by 0.75 both sides
x=125/0.75
x=Rs166.67
