Answer:
the answer would be B 36*27=27*36
Step-by-step explanation:
This is because the number placement changed with the numbers staying the same.
Hope this helps! :)
And have a great Friday!!
The cost of one pencil is $10:8=$1.25
The cost of 20 pencils: 1.25 x 20 = $25
Answer:
<em>37%</em>
Step-by-step explanation:
Add up the percentages and subtract them by 1.00:
- 35% & 28% = 0.35 & 0.28
- 0.35 + 0.28 = 0.63
- 1.00 - 0.63 = 0.37
- 0.37 = 37%
Good luck! :)
Answer: A 28.50 sq. u
Step-by-step explanation:
In the given figure , radius of the circle : r= 10 u
Central angle made by Arc ED: 
= 90° ( right angle )
Now , the area of the segment is given by :-
Area of segment = Area of sector (ECD) - Area of triangle(ECD) (i)
Formula : Area of right triangle = 0.5 x Base x Height
Area of sector = 
Using above formulas in (i) and substituting corresponding values , we get
Area of segment =
Hence, the correct answer is A 28.50 sq. u
We have to define an interval about the mean that contains 75% of the values. This means half of the values will lie above the mean and half of the values lie below the mean.
So, 37.5% of the values will lie above the mean and 37.5% of the values lie below the mean.
In a Z-table, mean is located at the center of the data. So the position of the mean is at 50% of the data. So the position of point 37.5% above the mean will be located at 50 + 37.5 = 87.5% of the overall data
Similarly position of the point 37.5% below the mean will be located at
50 - 37.5% = 12.5% of the overall data
From the z table, we can find the z value for both these points. 12.5% converted to z score is -1.15 and 87.5% converted to z score is 1.15.
Using these z scores, we can find the values which contain 75% of the values about the mean.
z score of -1.15 means 1.15 standard deviations below the mean. So this value comes out to be:
150 - 1.15(25) = 121.25
z score of 1.15 means 1.15 standard deviations above the mean. So this value comes out to be:
150 + 1.15(25) = 178.75
So, the interval from 121.25 to 178.75 contains the 75% of the data values.
