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iogann1982 [59]
3 years ago
11

C is the center of the circle. Find the area of the segment shown in the figure,

Mathematics
1 answer:
Semmy [17]3 years ago
6 0

Answer: A 28.50 sq. u

Step-by-step explanation:

In the given figure , radius of the circle : r= 10 u

Central angle made by Arc ED: \theta= 90° ( right angle )

Now , the area of the segment is given by :-

Area of segment = Area of sector (ECD) - Area of triangle(ECD) (i)

Formula : Area of right triangle = 0.5 x Base x Height

Area of sector = \dfrac{\theta}{360^{\circ}}\times\pi r^2

Using above formulas in (i) and substituting corresponding values , we get

Area of segment =

\dfrac{90^{\circ}}{360^{\circ}}\times\pi (10)^2-0.5\times10\times10\\\\=\frac{1}{4}(3.14)(100)-50\\\\=78.5-50=28.5\ sq.u

Hence, the correct answer is A 28.50 sq. u

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I did 40 minus 19 to get 21, and the divided 21 by 3 to get 7 sheets of paper.

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====================================

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Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

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