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iogann1982 [59]
3 years ago
11

C is the center of the circle. Find the area of the segment shown in the figure,

Mathematics
1 answer:
Semmy [17]3 years ago
6 0

Answer: A 28.50 sq. u

Step-by-step explanation:

In the given figure , radius of the circle : r= 10 u

Central angle made by Arc ED: \theta= 90° ( right angle )

Now , the area of the segment is given by :-

Area of segment = Area of sector (ECD) - Area of triangle(ECD) (i)

Formula : Area of right triangle = 0.5 x Base x Height

Area of sector = \dfrac{\theta}{360^{\circ}}\times\pi r^2

Using above formulas in (i) and substituting corresponding values , we get

Area of segment =

\dfrac{90^{\circ}}{360^{\circ}}\times\pi (10)^2-0.5\times10\times10\\\\=\frac{1}{4}(3.14)(100)-50\\\\=78.5-50=28.5\ sq.u

Hence, the correct answer is A 28.50 sq. u

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Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations. (-4, 9), (0,
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Answer:

\boxed{y=2x^2+4x-7}

Step-by-step explanation:

Let the quadratic function be

y=ax^2+bx+c


We substitute (-4,9) into the equation to obtain;


9=a(-4)^2+b(-4)+c


\Rightarrow 9=16a-4b+c---(1)


We substitute (0,-7) to obtain;


-7=a(0)^2+b(0)^2+c


\Rightarrow c=-7---(2)


We finally substitute (1,-1) to obtain;


-1=a(1)^2+b(1)^2+c


\Rightarrow -1=a+b+c---(3)


We put equation (2) into equation (1) to get;


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16a-4b=16


\Rightarrow 4a-b=4---(4)


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\Rightarrow a+b=6---(5)


We add equation (4) and (5) to get;

4a+a=6+4



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We put a=2 into equation (5) to get;


2+b=6


\Rightarrow b=6-2


\Rightarrow b=4


The reqiured quadratic function is

y=2x^2+4x-7

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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