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s344n2d4d5 [400]
3 years ago
12

4 2/3 ÷ 5 6/9=? 5 4/9 × 6 7/9=?

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

1: 14/17

2:

Step-by-step explanation:

1:

4 2/3 ÷ 5 6/9 =

14/3 ÷ 51/9 =

14/3 • 9/51 =

14/1 • 3/51 =

42/51 =

14/17

2:

5 4/9 • 6 7/9 =

49/9 • 61/9 =

fraction: 2989/81  or mixed number: 36 73/81

Hopefully that is what you wanted!

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Bumek [7]
Answer is 5 sorry if I’m wrong
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2 years ago
The diameter of a Frisbee is 12 in. What is the area of the Frisbee?
Alina [70]

we know that

Area of the circle is equal to

A=\pi r^{2}

where

r is the radius

in this problem

diameter=12\ in \\ radius=diameter/2\\ radius=12/2\\ radius=6\ in

A=3.14* 6^{2}

A=113.04 in^{2}

therefore

the answer is the option

d. 113.04 sq. in.

8 0
3 years ago
Read 2 more answers
Find the area of a triangle bounded by the x-axis the line f(x)=5-5/3x and the line perpendicular to f(x)
viktelen [127]

Answer:

answer fx

Step-by-step explanation:

its fx because it works

7 0
2 years ago
What ia the angle of AOC and DOE
natulia [17]

(i) Angle AOC would equal 48°, as it is vertically opposite to angle DOB and they are therefore equal.


(ii) Angle DOE would equal 42°. We can see this because angles on a straight line add up to 180°, and 90 + 48 = 138, so we can do 180 - 138 = 42°.


I hope this helps!

4 0
2 years ago
Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

f' is greater than 0 when the curve is above the x-axis.

f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0.  That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

* Relative maximums at x=1

3 0
2 years ago
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