Julianne drew the line segment below. Use your ruler to measure the segment to the nearest fourth inch
1 answer:
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Answer:
The answer is the second option
Minimum = 203, Q1 =217, median = 230, Q3 = 245, maximum = 290
Step-by-step explanation:
First order the data from lowest to highest
203, 216, 217, 224, 224, 236, 245, 245 ,262 ,290
Minimun = 203
Maximum =290
Now divide the data in half
203, 216, 217, 224, 224, 236, 245, 245 ,262 ,290
Divide half of the first half of the data. The data of the medium is the first quartile
1) 203, 216, [217], 224, 224
Q1
Divide half of the second half of the data. The data of the medium is the third quartile
2) 236, 245, [245] ,262 ,290
Q3
The average between the two values that are in the center of the 10 ordered data is the median
203, 216, 217, 224, [224, 236], 245, 245 ,262 ,290
Median=230
The answer is the second option
Minimum = 203, Q1 =217, median = 230, Q3 = 245, maximum = 290
