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horrorfan [7]
3 years ago
13

What options does the Table Tools Layout contextual tab contain? Select three options.

Computers and Technology
2 answers:
alex41 [277]3 years ago
4 0

Answer:

This tab contains two tabs, Design and Layout that give you the ability to quickly format your table, insert or delete rows and columns, set the alignment for cells, and format the typography of the text in your table

Explanation:

Tresset [83]3 years ago
3 0

Answer:

A. modify text direction

C. insert rows and columns

E. split table

You might be interested in
C++ code only
nordsb [41]

Using the computational language C++ it is possible to write a code is possible to create a function that stores items like this:

<h3>Writting the code in C++: </h3>

<em>//Header files</em>

<em>#include <iostream></em>

<em>#include <string></em>

<em>#include <fstream></em>

<em>using namespace std;</em>

<em>//Class inventoryItem</em>

<em>class inventoryItem</em>

<em>{</em>

<em>public:</em>

<em>//Variable declaration</em>

<em>string itemName;</em>

<em>string itemNumber;</em>

<em>double itemPrice;</em>

<em>int itemQuantity;</em>

<em>};</em>

<em>//implementation of menuItems() function.</em>

<em>void menuItems()</em>

<em>{</em>

<em>// Display the Menu</em>

<em>cout << "=============================\n";</em>

<em>cout << " 1) Add an item to memory\n"</em>

<em><< " 2) Search memory for an item \n"</em>

<em><< " 3) List what's in memory\n"</em>

<em><< " 4) Total value on hand\n"</em>

<em><< " 5) Save to a file\n"</em>

<em><< " 6) Read from a file\n"</em>

<em><< " 0) Exit Program" << endl;</em>

<em>}</em>

<em>//main method.</em>

<em>int main()</em>

<em>{</em>

<em>//variable declaration.</em>

<em>int mnuChoice, cn = 0, d;</em>

<em>string n;</em>

<em>double sum = 0, c;</em>

<em>int temp;</em>

<em>string a, b;</em>

<em>string inputBuffer;</em>

<em>inventoryItem items[100];</em>

<em>ifstream inventoryFile("inventory.txt");</em>

<em>if (inventoryFile)</em>

<em>{</em>

<em>//store the data from the file to memory.</em>

<em>while (!(inventoryFile.eof()))</em>

<em>{</em>

<em>inventoryFile >> items[cn].itemName;</em>

<em>inventoryFile >> items[cn].itemNumber;</em>

<em>inventoryFile >> inputBuffer;</em>

<em>items[cn].itemPrice = atof(inputBuffer.c_str());</em>

<em>inventoryFile >> inputBuffer;</em>

<em>items[cn].itemQuantity = atoi(inputBuffer.c_str());</em>

<em>cn++;</em>

<em>}</em>

<em>inventoryFile.close();</em>

<em>ifstream inventoryFile("inventory.txt");</em>

<em>ofstream fout;</em>

<em>fout.open("inventory.txt");</em>

<em>do</em>

<em>{</em>

<em>menuItems();</em>

<em>cout << cn << " items stored." << endl;</em>

<em>// Prompt and read choice form the user</em>

<em>cout << "Enter your choice: ";</em>

<em>cin >> mnuChoice;</em>

<em />

<em>switch (mnuChoice)</em>

<em>{</em>

<em>//Add a new inventory item to the data in memory.</em>

<em>case 1:</em>

<em>// Prompt and read name of the item from the user</em>

<em>cout << "Enter name of the item: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemName = inputBuffer;</em>

<em>// Prompt and read itemNumber from the user</em>

<em>cout << "Enter the itemNumber: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemNumber = inputBuffer;</em>

<em>// Prompt and read itemPrice from the user</em>

<em>cout << "Enter the itemPrice: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemPrice = atof(inputBuffer.c_str());</em>

<em>// Prompt and read itemQuantity from the user</em>

<em>cout << "Enter the itemQuantity: ";</em>

<em>cin >> inputBuffer;</em>

<em>items[cn].itemQuantity = atoi(inputBuffer.c_str());</em>

<em>cn++;</em>

<em>break;</em>

<em>//Search the inventory for an item by inventory number.</em>

<em>case 2:</em>

<em>temp = 0;</em>

<em>cout << "Enter inventory itemNumber: ";</em>

<em>cin >> n;</em>

<em>for (int i = 0; i < cn&&temp != 1; i++)</em>

<em>{</em>

<em>// If found, print the stored info</em>

<em>if (items[i].itemNumber.compare(n) == 0)</em>

<em>{</em>

<em>// Display the stored information</em>

<em>cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;</em>

<em>cout << items[i].itemName << "\t " << items[i].itemNumber << " \t" << items[i].itemPrice << "\t " << items[i].itemQuantity << endl;</em>

<em>temp = 1;</em>

<em>}</em>

<em>}</em>

<em>// otherwise print 'not found'.</em>

<em>if (temp == 0)</em>

<em>{</em>

<em>cout << "Not found!!!" << endl;</em>

<em>}</em>

<em>break;</em>

<em>//List the inventory on the screen</em>

<em>case 3:</em>

<em>cout << "The data in the memory is:" << endl;</em>

<em>cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>cout << items[i].itemName << "\t " << items[i].itemNumber << "\t " << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;</em>

<em>}</em>

<em>break;</em>

<em>// Calculate the total value on hand.</em>

<em>case 4:</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>// The sum is the accumulation of all the (quantities * prices).</em>

<em>sum += items[i].itemPrice*items[i].itemQuantity;</em>

<em>}</em>

<em>cout << "sum value on hand: " << sum << endl;</em>

<em>break;</em>

<em>// Save the inventory data in the given file</em>

<em>case 5:</em>

<em>for (int i = 0; i < cn; i++)</em>

<em>{</em>

<em>if (i == cn - 1)</em>

<em>{</em>

<em />

<em>fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity;</em>

<em>}</em>

<em>else</em>

<em>{</em>

<em />

<em>fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;</em>

<em>}</em>

<em>}</em>

<em>break;</em>

<em>// Read the data from the file</em>

<em>case 6:</em>

<em>while (!(inventoryFile.eof()))</em>

<em>{</em>

<em>inventoryFile >> a;</em>

<em>inventoryFile >> b;</em>

<em>inventoryFile >> inputBuffer;</em>

<em>c = atof(inputBuffer.c_str());</em>

<em>inventoryFile >> inputBuffer;</em>

<em>d = atoi(inputBuffer.c_str());</em>

<em>// Dsiplays the data in the file</em>

<em />

<em>cout << a << " " << b << " " << c << " " << d << endl;</em>

<em>}</em>

<em>break;</em>

<em>}</em>

<em>// Check the menu choice is not equal to 0,</em>

<em>//if it is equal exit from the loop</em>

<em>} while (mnuChoice != 0);</em>

<em>// File closed</em>

<em>fout.close();</em>

<em>inventoryFile.close();</em>

<em>}</em>

<em>// If the inventory file does not exist</em>

<em>// and then display the error message.</em>

<em>else</em>

<em>{</em>

<em>cout << "File does not exist!" << endl;</em>

<em>}</em>

<em />

<em>return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/17544466

#SPJ1

5 0
2 years ago
What are some examples for Environmental Technology? Also some negative and positive effects?
lakkis [162]
Wave energy and wind power (also hydroelectric dams as well), they create energy without pollution but need a lot of maintenance and some people disagree with their aesthetic influence of the countryside as they are very industrial looking  <span />
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I need help translating this Morse code here it is
Goshia [24]

Answer:

NEVER GONNA GIVE YOU UP NEVER GONNA LET YOU DOWN

Wherever this is from it is a Rick roll.

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PLS HURRY!!!<br> Look at the image below
trasher [3.6K]

The correct choices are:

having the user guess a number and keep guessing till they get it right

allowing the user to enter their best friends names without saying how many friends they can have

writing a program to average numbers without requiring the user to count the numbers.

4 0
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Which of the following reflects the order of operations
lorasvet [3.4K]

Answer: PEMDAS

Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction

Explanation:

3 0
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