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Sedaia [141]
3 years ago
9

YASHARI earns $27,000 per year, is single, and lives in Wyoming. She has $7000 in Direct Subsidized loans and another $19,000 in

Direct Unsubsidized loans. She is trying to save up an emergency fund of at least 6 months’ take-home pay, so she’s torn about how much she should devote to her student loans and how much to the emergency fund every month.
How do you think Yashari should prioritize between her emergency fund goal and her student loan payments?
Computers and Technology
1 answer:
RideAnS [48]3 years ago
7 0

Answer:

Income-Contingent Repayment (approximately $37,812), 21 years

Explanation:

With a monthly payment limit of 20% of her discretionary income and no loan forgiveness eligibility, Yashari would pay $147-142 per month, $37,812 total, until December 2043 (21 years from 2022).

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Write a program whose input is a character and a string, and whose output indicates the number of times the character appears in
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Answer:

Here is the C++ program:

#include <iostream> // to include input output functions

using namespace std; // to identify objects like cin cout

int counter(string userString, char character) { //function counter

   int count = 0;   // counts the no of times a character appears in the string

   for (int i=0;i<userString.length();i++)  

// loop to move through the string to find the occurrence of the character

       if (userString[i] == character) //if characters is found in the string

           count++;   //counts the occurrence of the character in the string

   return count; }   //returns the no of times character occurs in the string

int main() { //start of the main() function body

   string s; // stores the string entered by the user

   cout<<"Enter a string: "; //prompts user to enter the string

   cin>>s; //reads the string from user

   char ch; //stores the character entered by the user

   cout<<"Enter a character: "; //prompts user to enter a character

   cin>>ch; //reads the character from user

   cout << counter(s, ch) << endl; }  

//calls counter function to find the number of times a character occurs in the //string

Explanation:

The counter function works as following:

It has a count variable which stores the number of occurrences of a character in the userString.

It uses a for loop which loops through the entire string.

It has i position variable which starts with the first character of the string and checks if the first character of userString matches with the required character.

If it matches the character then count variable counts the first occurrence of the character and in the userString and is incremented to 1.

If the character does not match with the first character of the userString then the loops keeps traversing through the userString until the end of the userString is reached which is specified by the length() function which returns the length of the string.

After the loop ends the return count statement is used to return the number of occurrences of the character in the userString.

The main() function prompts the user to enter a string and a character. It then calls counter() function passing string s and character ch arguments to it in order to get the number of times ch appears in s.

The output is attached in a screenshot.

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