The equation in this problem is: 2Pb(NO3)2(s) --> 2PbO(s)
+ 4NO2(g) + O2(g)
And the question is what the pressure in the cylinder is
after decomposition and cooling to a temperature of 300 K.
Solution:
Moles of Pb (NO3)2 = 3.31/331 = 0.0100
2 moles of Pb (NO3)2 will decay to mold 4 moles of NO2 and 1 mole of O2. So
0.0100 moles of Pb (NO3)2 will form 0.02 moles of NO2 and 0.00500 moles of
O2
Then use the formula: PV = nRT.
P = (0.02 + 0.005) * 0.082 * 300 / 1.62
= 0.380 atm
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It 1:1 I had an online review and thats the answer it told me it was.
-Hope this helped you
T = final temperature of the block
T₀ = initial temperature of the block = 23.4 °C
Q = energy lost from the wooden block = - 759 J
c = specific heat capacity of wood = 1.716 J/(g °C)
m = mass of the wooden block = 27.2 g
Heat lost from the block is given as
Q = m c (T - T₀)
inserting the values
- 759 = (27.2) (1.716) (T - 23.4)
T = 7.1 °C
Answer:
Moles of zinc chloride produced are 0.09942 moles.
Explanation:
Mass of zinc used = 6.5 g
Moles of zinc =
According to reaction, 1 mol of zinc gives 1 mole of zinc chloride,then 0.09942 moles of zinc will give :
of zinc chloride
Moles of zinc chloride produced are 0.09942 moles.
The number decreases as the amount of electrons decreases
hope that helps
