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inessss [21]
2 years ago
5

Explain why the sign of the slope of a regression line must be thesame as the sign of the correlation coeffi cient.

Chemistry
2 answers:
Umnica [9.8K]2 years ago
8 0

Answer:

The calculation of a standard deviation involves taking the positive square root of a nonnegative number. As a result, both standard deviations in the formula for the slope must be nonnegative. ... Therefore the sign of the correlation coefficient will be the same as the sign of the slope of the regression line.

Explanation:

have a nice day

MAXImum [283]2 years ago
6 0

Answer:

The calculation of a standard deviation involves taking the positive square root of a nonnegative number. As a result, both standard deviations in the formula for the slope must be nonnegative. ... Therefore the sign of the correlation coefficient will be the same as the sign of the slope of the regression line.

Explanation:

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How many atoms are in 57.5 liters of xenon gas at STP
TiliK225 [7]

Answer:

1.55 × 10²⁴ atoms Xe

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 57.5 L Xe at STP

[Solve] atoms Xe

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 57.5 \ L \ Xe(\frac{1 \ mol \ Xe}{22.4 \ L \ Xe})(\frac{6.022 \cdot 10^{23} \ atoms \ Xe}{1 \ mol \ Xe})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 1.54583 \cdot 10^{24} \ atoms \ Xe

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.54583 × 10²⁴ atoms Xe ≈ 1.55 × 10²⁴ atoms Xe

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Answer:

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This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.

Hence, the nitro group makes the pyrinde ring more electron deficient

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