All categories

2 years ago

Explain why the sign of the slope of a regression line must be thesame as the sign of the correlation coeffi cient.

Chemistry

2 answers:

Umnica [9.8K]2 years ago

8 0

Answer:

The calculation of a standard deviation involves taking the positive square root of a nonnegative number. As a result, both standard deviations in the formula for the slope must be nonnegative. ... Therefore the sign of the correlation coefficient will be the same as the sign of the slope of the regression line.

Explanation:

have a nice day

MAXImum [283]2 years ago

6 0

Answer:

Explanation:

You might be interested in

23 grams of sodium reacts with 293 cm 3 of water that is initially at 298 k. it produces an enthalpy change of 197 kj. what is t

m_a_m_a [10]

448 K is the final temperature of the water.

<h3>What is specific heat capacity?</h3>

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given,

the mass of Na is 23 g

The volume of water = 293 cm3

Mass of water = 293 g

Total solution mass = 23 g + 293 g = 316 g

Specific heat capacity of water = 4.18 J/Kg

The equation relating mass, heat, specific heat capacity and temperature change is:

q = mcΔT

197 kJ = 316 g x 4.18 J/Kg x ( $T_{finals} - T_ {initial}$ )

197 kJ = 316 g x 4.18 J/Kg x ( $T_{finals}$ -298 K)

0.1491429956 x 1000 = $T_{finals}$ -298 K

149.1429956 + 298 = $T_{finals}$

447.1429956 = $T_{finals}$

448 K = $T_{finals}$

Hence, 448 K is the final temperature of the water.

<h3>What does a high specific heat capacity mean?</h3>

A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.

Learn more about specific heat capacity here:

brainly.com/question/2530523

#SPJ4

5 0

2 years ago

5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H

cricket20 [7]

We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572. That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

7 0

3 years ago

determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth m

mamaluj [8]

This is an incomplete question, here is a complete question.

Determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices.

(a) $1s^22s^22p^63s^23p^5$

(b) $1s^22s^22p^63s^23p^63d^74s^2$

(d) $1s^22s^22p^63s^23p^63d^4s^1$

Answer :

(a) $1s^22s^22p^63s^23p^5$ → Halogen

(b) $1s^22s^22p^63s^23p^63d^74s^2$ → Transition metal

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$ → Transition metal

(d) $1s^22s^22p^63s^23p^63d^4s^1$ → Transition metal

Explanation :

Inert gas : These are the gases which lie in group 18.

Their general electronic configuration is: $ns^2np^6$ where n is the outermost shell.

Halogen : These are the elements which lie in group 17.

Their general electronic configuration is: $ns^2np^5$ where n is the outermost shell.

An alkali metal : These are the elements which lie in group 1.

Their general electronic configuration is: $ns^1$ where n is the outermost shell.

An alkaline earth metal : These are the elements which lie in group 2.

Their general electronic configuration is: $ns^2$ where n is the outermost shell.

Transition elements : They are the elements which lie between 's' and 'p' block elements. These are the elements which lie in group 3 to 12. The valence electrons of these elements enter d-orbital.

Their general electronic configuration is: $(n-1)d^{1-10}ns^{0-2}$ where n is the outermost shell.

(a) $1s^22s^22p^63s^23p^5$

The element having this electronic configuration belongs to the halogen family.

(b) $1s^22s^22p^63s^23p^63d^74s^2$

The element having this electronic configuration belongs to the transition family.

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$

The element having this electronic configuration belongs to the transition family.

(d) $1s^22s^22p^63s^23p^63d^4s^1$

The element having this electronic configuration belongs to the transition family.

4 0

3 years ago

A metallic conductor moving at a constant speed in a magnetic field may develop a voltage across it. this is an example of _____

marysya [2.9K]

A metallic conductor moving at a constant speed in a magnetic field may develop a voltage across it. This is an example of Motional emf
Hope this helps!

3 0

3 years ago

6) What is located in the nucleus?

jek_recluse [69]

Answer:

Protons and Neutrons are found in the nucleus

7 0

3 years ago