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3 years ago

HELP ALGEBRA IS KILLING ME IMAGE IS BELOW

Mathematics

1 answer:

djyliett [7]3 years ago

6 0

Answer:

58240

Step-by-step explanation:

1425 ------ 45600

1820 ------ x

1425*x = 1425x

45600*1820 = 82992000

1425x = 82992000

82992000/1425 = x

58240 = x

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Determine the first four terms of the sequence in which the nth term is...

Anon25 [30]

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5

The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6

The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7

The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

7 0

3 years ago

Read 2 more answers

1) If the alpha level is changed from α = .05 to α = .01, what happens to boundaries for the critical region?

Alexxandr [17]

Answer:

1) a. Move farther into the tails

2) a. Decreases

Step-by-step explanation:

Hello!

Let's say for example that you are making a confidence interval for the mean, using the Z-distribution:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{Sigma}{\sqrt{n} }$

Leaving all other terms constant, this are the Z-values for three different confidence levels:

90% $Z_{0.95}= 1.648$

95% $Z_{0.975}= 1.965$

99% $Z_{0.995}= 2.586$

Semiamplitude of the interval is

d= $Z_{1-\alpha /2}$ * $\frac{Sigma}{\sqrt{n} }$

Then if you increase the confidence level, the value of Z increases and so does the semiamplitude and amplitude of the interval:

↑d= ↑ $Z_{1-\alpha /2}$ * $\frac{Sigma}{\sqrt{n} }$

They have a direct relationship.

So if you change α: 0.05 to α: 0.01, then the confidence level 1-α increases from 0.95 to 0.99, and the boundaries move farther into the tails.

The significance level of a hypothesis test is the probability of committing a Type I error.

If you decrease the level from 5% to 1%, then logically, the probability decreases.

I hope this helps!

5 0

3 years ago

O curso de inglês de Carolina teve duração de 4 semestres e 2 meses . quantos tempo durou esse curso de Carolina ?

Afina-wow [57]

Answer:

a 26 meses gracias por los puntos

5 0

3 years ago

The Department of Commerce in a particular state has determined that the number of small businesses that declare bankruptcy per

skad [1K]

Answer:

B) 0.1487

Step-by-step explanation:

Let $X$ be the discrete random variable that represents the number of events observed over a given time period. If $X$ follows a Poisson distribution, then the probability of observing $k$ events over the time period is:

$P(X=k)=\frac{\lambda^{k} *e^{-\lambda} }{k!}$

Where:

$\lambda=Mean\\k=number\hspace{3}of\hspace{3}events\\e=Euler's\hspace{3}number$

So, the probability that exactly 5 bankruptcies occur next month is:

$P(X=5)=\frac{6.4^{5} *e^{-6.4} }{5!} =\frac{17.84083537}{120} =0.1486736281\approx0.1487$

4 0

3 years ago

HELP ME PLS PLS PLS PLS

Kipish [7]

Answer:

y=-6/4x-4

Step-by-step explanation:

8 0

2 years ago