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2 years ago

5

Using the 45°-45°-90° triangle theorem, find the value of h, the height of the wall. 6. 5 ft 6. 5 StartRoot 2 EndRoot ft 13 ft 1

3 StartRoot 2 EndRoot ft.

1 answer:

navik [9.2K]2 years ago

4 0

35 es mucho así que será 27 i think is 18

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Answer ease so confused

Levart [38]

$3 - 5 \sqrt{15x} + \sqrt{15x} - 25x \\ \\ 3 - 4 \sqrt{15x} - 25x$
I'm confused too but that what i got

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2 years ago

Willie and anjali each improved their yards by planting daylilies and ivy. They bought their supplies from the same store. Willi

Fiesta28 [93]

Answer:the cost of one day lily = $9 and cost of one pot of ivy = $2

Step-by-step explanation:

Step 1

let day lilies be rep as d

and ivy be represented as i

So that The expression for what Willie spent on 12 day lilies and 4 pots of ivy = $116 be

12 d+ 4i = 116 ---- equation 1

and for Anjali spending $60 on 6 day lilies and 3 pots of ivy be

6d+ 3i = $60------ equation 2

Step 2 --- Solving

12 d+ 4i = 116 ---- equation 1

6d+ 3i = $60------ equation 2

Multiply equation 2 by (2) and subtracting equation 1 from it

12d+ 6i= 120

--12 d+ 4i = 116

2 i= 4

i = 4/2 = 2

TO find d, putting the value of i = 2 in equation 1 and solving

12d+ 4(2) = 116

12d= 116-8

12d= 108

d= 108/12= 9

Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2

5 0

2 years ago

Draw a basketball with a vertical, angled, and horizontal cut

ANTONII [103]

That is what it looks like

8 0

2 years ago

Please show your work and explain it.

Maru [420]

Answer:

$f(x)=\dfrac{x+2}{2(x-2)}$

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

$\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}$

Next we factor what we can so we can further simplify the rest of the equation:

$=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\$

We can now cancel out (x+2)

$=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}$

Next we factor out even more:

$=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}$

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

$=\dfrac{(x+2)(1)}{(x-2)(2)}$

And we can now simplify it to:

$=\dfrac{x+2}{2(x-2)}$

6 0

3 years ago

Write a variable expression for 4 fewer than a number s.

rjkz [21]

S - 4

s minus 4 is the answer. s is the number and this is 4 fewer than s. Hope this helps.

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2 years ago