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True [87]
3 years ago
8

¿Qué se quebraron los niños?

Mathematics
1 answer:
hjlf3 years ago
7 0
The first option. -aron is the conjugation for a plural (they) form.
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What is the greatest common factor of 63b^2c^4 and 42b^3c^2
Arte-miy333 [17]

Factor out the GCF of  

21

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+

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Tap for fewer steps...

Factor out the GCF of  

21

b

2

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2

from each term in the polynomial.

Tap for fewer steps...

Factor out the GCF of  

21

b

2

c

2

from the expression  

63

b

2

c

4

.

21

b

2

c

2

(

3

c

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)

+

42

b

3

c

2

Factor out the GCF of  

21

b

2

c

2

from the expression  

42

b

3

c

2

.

21

b

2

c

2

(

3

c

2

)

+

21

b

2

c

2

(

2

b

)

Since all the terms share a common factor of  

21

b

2

c

2

, it can be factored out of each term.

21

b

2

c

2

(

3

c

2

+

2

b

)

The greatest common factor  

GCF

is the term in front of the factored expression.

21

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c

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6 0
3 years ago
Read 2 more answers
Nine hundred light bulbs are packaged and shipped to a retail store. Thirteen percent of the light bulbs arrive broken. Which eq
Over [174]

Answer:

3

Step-by-step explanation:

7 0
3 years ago
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If 3 Onions Weigh 0.75lb how much do 10 onions weigh
fomenos
First find out how much one onion weighs so divide 0.75 by 3. This gets you 0.25. Now all you need to do is multiply the weight of one onion by 10, 0.25 x 10 = 2.5
3 0
3 years ago
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g A coin where the probability of heads is 0.3 is flipped 2000 times. Use the normal approximation to the binomial distribution
matrenka [14]

Title:

<h2>See the explanation.</h2>

Step-by-step explanation:

The coin is to be flipped 2000 times.

The probability of getting a head is 0.3.

It is given that, we need to get a head in between 575 and 618 times.

If we will get 575 heads then we will get (2000 - 575) tails.

Hence, if we take that we want to get n times head, then we will get (2000 - n) times tail.

The probability of not getting a head is (1 - 0.3) = 0.7.

The probability of getting n times head is ^{2000}C_n (0.3)^n \times (0.7)^{2000 - n}.

The required probability is ∑ ^{2000}C_n (0.3)^n \times (0.7)^{2000 - n}, where 575 \leq n \leq 618.

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3 years ago
{{{WILL MARK AS BRANLIEST AND WORTH 18 POINTS!!!}}
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7.1 ×
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