All categories

3 years ago

A salesperson earns a salary of $40,000 per year plus 7% commission on sales of $120,000. what is his total income?

Mathematics

1 answer:

lesya [120]3 years ago

5 0

40,000 + 0.07(120,000) =
40,000 + 8,400 =
$ 48,400 per year <===

You might be interested in

Which ordered pairs are solutions to the inequality y−4x≤−6 ?

amid [387]

I think it is A, (-2,-14)

7 0

3 years ago

Sketch a graph that is discrete, has a maximum, does not pass through the origin, and is an absolute value function

Stella [2.4K]

Um.. I can't sketch a graph on here.
A discrete function can't be an absolute value function because an absolute value function is continuous. But, the function equation can be as simple as
f(x) = - | x + 1 |
Just don't connect the dots when you draw it and boom, you're done.

6 0

3 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

3 years ago

What are reasons A,B,and C in the proof?

Vlad [161]

Answer:

Option D is correct.

Explanation:

Commutative Property of Multiplication define that two numbers can be multiplied in any order.

i.e $a\times b =b \times a$

Distributive property of multiplication states that when a number is multiplied by the sum of two numbers i.e, the first number can be distributed to both of those numbers and multiplied by each of them separately.

$a \times (b+c) = a\times b+ a\times c$