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Tems11 [23]
3 years ago
14

What is the circumference of a 45 m circle

Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0
Circumference:141.3cm
Kobotan [32]3 years ago
3 0
<span>to solve circumference of a circle is diameter times pi.
C=141.3 cm</span>
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Evaluate the expression (3.2)².​
Ludmilka [50]

Answer:

36

Step-by-step explanation:

3*2=6

6^2=6*6

=36

7 0
2 years ago
Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

6 0
3 years ago
100 POINTS!!!!!!
Andrews [41]

Answer:

A 4x2=7-15 X=

Step-by-step explanation:

B como dedos de los dedos de losdos para el desayuno

C te como para el chico del

4 0
3 years ago
2.At a local bank 7 out of 12 12 employees have a master's degree. If the bank has 100 employees,
Komok [63]
The correct answer is 58
4 0
3 years ago
Which of the following is a trinomial with a constant term?
Cloud [144]

Option D x+2y+10 .

A trinomial with a constant term will have three terms, and one of those terms will be a constant, which is a number.

we also know about the Constant

A fixed value. In Algebra, a constant is a number on its own, or sometimes a letter such as a, b or c to stand for a fixed number.

Some relatable terms are :

Monomial: Polynomial having a single term.

Binomial: Polynomial having two terms.

Trinomial: Polynomial having three terms.

In given option we'll define

in option A there is no constant .

option B there i sonly given x which is also not constant.

further in option c it is simply binomial in which only two terms are given without constant .

so at last conclusion is in option D there are three terms are given with one constant which is number 10 .

x+2y+10 is trinomial with a constant.

For more information about Polynomial

visit  brainly.in/question/3793499

#SPJ9

8 0
2 years ago
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