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What are the first and the last physical memory addressesaccessible using

Misha Larkins [42]

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

NOTE-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

10000 +00000 = 10000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

10000 +0FFFF =1FFFF (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

0FFF0 +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

0FFF0 +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

00010 +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

00010 +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

E0000 +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

E0000 +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

10020 +00000=10020 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

10020 +0FFFF =2001F (from note)

6 0

3 years ago

To obtain the desired speedup, make sure your new function recursively calls itself no more than once in the body of the method.

sertanlavr [38]

Answer:

the answer is going to be a. true

8 0

3 years ago

We will use linear interpolation in a C program to estimate the population of NJ between the years of the census, which takes pl

nikklg [1K]

Answer:

See explaination for program code

Explanation:

program code below:

#include<stdio.h>

int main()

{

//file pointer to read from the file

FILE *fptr;

//array to store the years

int years[50];

//array to store the population

float population[50];

int n = 0, j;

//variables for the linear interpolation formula

float x0,y0,x1,y1,xp,yp;

//opening the file

fptr = fopen("njpopulation.dat", "r");

if (fptr != NULL)

{

//reading data for the file

while(fscanf(fptr, "%d %f", &years[n], &population[n]) == 2)

n++;

//prompting the user

int year = -1;

printf("Enter the years for which the population is to be estimated. Enter 0 to stop.\n\n");

while(year != 0)

{

printf("Enter the year (1790 - 2010) : ");

scanf("%d", &year);

if (year >= 1790 && year <= 2010)

{

//calculating the estimation

xp = year;

for (j = 0; j < n; j++)

{

if (year == years[j])

{

//if the year is already in the table no nedd for calculation

yp = population[j];

}

else if (j != n - 1)

{

//finding the surrounding census years

if (year > years[j] && year < years[j + 1])

{

//point one

x0 = years[j];

y0 = population[j];

//point two

x1 = years[j + 1];

y1 = population[j + 1];

//interpolation formula

yp = y0 + ((y1-y0)/(x1-x0)) * (xp - x0);

}

printf("\nEstimated population for year %d : %.2f\n\n", year, yp);

}

else if (year != 0)

{

printf("\nInvalid chioce!!\n\n");

}

printf("\nAborting!!");

}

else

{

printf("File cannot be opened!!");

}

close(fptr);

return 0;

}

OUTPUT :

Enter the years for which the population is to be estimated. Enter 0 to stop.

Enter the year (1790 - 2010) : 1790

Estimated population for year 1790 : 184139.00

Enter the year (1790 - 2010) : 1855

Estimated population for year 1855 : 580795.00

Enter the year (1790 - 2010) : 2010

Estimated population for year 2010 : 8791894.00

Enter the year (1790 - 2010) : 4545

Invalid chioce!!

Enter the year (1790 - 2010) : 1992

Estimated population for year 1992 : 7867020.50

Enter the year (1790 - 2010) : 0

Aborting!!

5 0

3 years ago

Code a call to the function anotherFunc passing the array myints.

mario62 [17]

Answer:

d)anotherFunc(myints);

Explanation:

When we call a function we just have to pass the names of the arguments to the function.In case of arrays we also just have to pass the name of the array.We don't have to worry about the square brackets.So the function call will be like this.

anotherFunc(myints);

Hence the answer is option d.

4 0

3 years ago

Iman has 48 months to save $18,000, the maximum amount he estimates his first year of college will cost. He does not want to dep

natita [175]

The minimum amount that Iman should save is $375

8 0

3 years ago

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