Answer:
the command still has to be carried out.
Answer:
int main() {
int n;
cout<<"Enter the integer n"<<endl;
cin>>n;
if(n<1 || n>10)
{
while(n>10 || n<1)//taking input if the number is not within range..
{
cout<<"Enter the number again"<<endl;
cin>>n;
}
activity(n);//calling activity with the n..
}
return 0;
}
Explanation:
Above written is the main function in which a prompting an integer between 1 and 10 if it is not within range then again taking input.Then after that calling activity with n as argument.
Answer:
I think Windows 98 or XP it's one of those
Explanation:
Answer:
Following are the program in python language
def prob3_6(k): #function definition
c = 0 #variable declaration
while k != 1: #iterating the while loop
print(k) #print k
if k % 2 == 0:#check if condition
k= k // 2 #divisible by 2
else: #else condition
k = k * 3 + 1
c = c + 1
print(k) #print k
print c #print count
prob3_6(3)#function call
Output:
3
10
5
16
8
4
2
1
7
Explanation:
Following are the description of program
- Create a function "prob3_6" in this function we passing an integer parameter of type "int" named "k".
- Inside that function we declared a variable "c" of type "int" that is used for counting purpose .
- After that we iterated the while for print the value of when it is not equal to 1 .
- We check if condition when k gives 0 on modulus then k is divisible by 2 otherwise else block will be executed in the else part we multiply by 3 to k and add 1 to the k variable .
- Finally print "k" and "c"
Hi,
The word you are looking for is "programs".
Hope this helps.
r3t40
