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ipn [44]
3 years ago
6

Assume a trucker changes his tire every 40,000 miles, and that he starts with a brand new set of tires, how many sets of tires w

ill he use in a year.
Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0
40 sets of tires. I learned this by looking up your question because it is incomplete.
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Ineed help help me please
melamori03 [73]
The symbol ₁₂P₉ represents the permutations of 9  quantities out of 12.
By definition,
_{12}P_{9} =  \frac{12!}{(12-9)!} = \frac{12!}{3!}

From the calculator,
12! = 479,001,600
3! = 6

Therefore
₁₂P₉ = 479001600/6 = 79,833,600

Answer: 79,833,600
8 0
3 years ago
Aisha and jordan start by making a floor plan for their treehouWhich revision of these two sentences best shows that the coach b
irina1246 [14]

Answer: Statements 1 and 2 shows that the coach blowing the whistle happened first.

Step-by-step explanation: The coach blowing the whistle as the first event can be seen only from statements 1 and 2 only.

From statement 1, "the referee blew the whistle" was followed by "the team ran onto the field."

From statement 2, "before the team ran onto the field" shows clearly that one event took place "BEFORE" the one being reported and the one that occurred before this one was "the referee blew the whistle."

Statement 3 which is "the referee blew the whistle, BUT..." indicates that the whistle was meant to prevent the team from from running onto the field. So if the referee blew the whistle, but the team ran onto the field, it means the whistle blowing was not supposed to make them run onto the field.

Statement 4, which states that "the referee blew the whistle BECAUSE the team ran onto the field" indicates that, the reason for blowing the whistle was because the team ran onto the field which clearly shows that the team ran onto the field first before the referee blew the whistle.

Statement 5, "WHILE the team ran onto the field..." clearly shows that both events took place at the same moment, and so the referee blowing the whistle could not have occurred first.

8 0
3 years ago
Line AC and line DB intersect at point P. Solve for angle BPQ.
taurus [48]

Answer:

Angle BPQ = 64°

Step-by-step explanation:

4x + 12 +2x = 90

6x + 12 = 90

     - 12    -12

6x = 78

x = 13°

BPQ = ((4(13) + 12)°

           (52 + 12)°

            64°

8 0
2 years ago
Write the equation that modeled the sequence 63,-21,7,-7/3,7/9
Ilya [14]

Answer:

an = 63(-1/3)^(n-1)

Step-by-step explanation:

This is a geometric sequence with first term 63 and common ratio -1/3.

The equation for the nth term  is

an = 63(-1/3)^(n-1).

6 0
3 years ago
Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand
kvasek [131]

Answer:

(a)\frac{5}{7},\frac{1}{6} (b)\frac{1}{7},\frac{1}{6} (c)\frac{5}{7},\frac{2}{3},\frac{3}{5}

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag =7

(a)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing red marble  =\frac{\text{total red marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(b)

Probability of drawing red marble =\frac{\text{total red marble}}{\text{total marbles}}

                                                          =\frac{1}{7}

As marble is not returned to bag,

Probability of drawing white marble  =\frac{\text{total white marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(c)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing second blue marble  =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                         =\frac{4}{6}=\frac{2}{3}

As marble is not returned to the bag

Probability of drawing third blue marble   =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                    =\frac{3}{5}

8 0
3 years ago
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