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3 years ago

6

Assume a trucker changes his tire every 40,000 miles, and that he starts with a brand new set of tires, how many sets of tires w

ill he use in a year.

1 answer:

anyanavicka [17]3 years ago

6 0

40 sets of tires. I learned this by looking up your question because it is incomplete.

You might be interested in

How can you use substitution to solve a system of linear equations?

makvit [3.9K]

Step 1:
Solve one of the equations for either x = or y = .
Step 2:
Substitute the solution from step 1 into the other equation.
Step 3:
Solve this new equation.
Step 4:
Solve for the second variable.

Example 1: Solve the following system by substitution
Substitution Method Example
Solution:
Step 1: Solve one of the equations for either x = or y = . We will solve second equation for y.
solution step 1
Step 2: Substitute the solution from step 1 into the second equation.
solution step 2
Step 3: Solve this new equation.
solution step 3
Step 4: Solve for the second variable
solution step 4
The solution is: (x, y) = (10, -5)
Hope this helps!

6 0

3 years ago

What is the value of P(9.1)? What does it tell us about the side length and perimeter

nadya68 [22]

Answer:

the answer is 36.4

Step-by-step explanation:

you have to multiply it by 4 so it it will look like this 9.1*4=36.4

4 0

3 years ago

The amount of money on account it makes M for working H hours can be represented by the equation m = 29.4H what is the constant

ELEN [110]

29.4H is the equation

4 0

2 years ago

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

3 years ago

Read 2 more answers

The numerator of a fraction is 3 less then the denominator. If 1 is added to the numerator, the value of the fraction becomes 3/

andrew11 [14]

The fraction is $\frac{5}{8}$

Step-by-step explanation:

Let,

The denominator of fraction = x

Numerator of fraction = x-3

Fraction = $\frac{x-3}{x}$

According to given statement;

1 is added to the numerator, the value of the fraction becomes 3/4.

$\frac{x-3+1}{x}=\frac{3}{4}\\\\\frac{x-2}{x}=\frac{3}{4}$

Using cross multiplication

$4(x-2)=3*x\\4x-8=3x\\4x-3x=8\\x=8$

Fraction = $\frac{x-3}{x}=\frac{8-3}{8}=\frac{5}{8}$

Keywords: fraction, division

Learn more about fractions at:

#LearnwithBrainly

3 0

3 years ago