Let ab be a 2 digit number, then ab=10a+b, where a and b are digits, a≠0.
"the difference between the integer and the product of its two digits is 12"
10a+b - (a*b)=12
10a+b-ab=12
factorize b:
10a+b(1-a)=12
subtract 10 from both sides, to produce a factor (1-a) or (a-1) and then factorize:
10a-10+b(1-a)=2
10(a-1)+b(1-a)=2
(a-1)(10-b)=2
(a-1)(10-b) can be (1,2), (2, 1), (-1, -2), (-2, -1)
if a-1=1 and 10-b=2, then a=2, b=8
if a-1=2, and 10-b=1, then a=3, b=9
if a-1=-1, then a=0, which is not possible
if a-1=-2, then a=-1, which is not possible
so the solutions (a, b) are (2, 8) and (3, 9)
Then the integers are 28, 39
Answer: 28, 39
The answer is: $ 41.60 .
________________________________
0.8 $ 5200
____ * ______ = 0.8 * $ 52 = $ 41.60 .
100 1
______________________________________________
The lottery's anticipated worth is $80.
Given that,
The probability of receiving $125 is 0.25; the likelihood of receiving $100 is 0.3; and the likelihood of receiving $50 is 0.45.
A) EV=125*.2+100*.3+50*.5=$80
The lottery's anticipated worth is $80.
The expected value is obtained by multiplying each result by its likelihood.
The expected value of the lottery is then calculated by adding up all of these.
This is what we have: ;;
125(0.2) + 100(0.3) + 50(0.5) (0.5)
= 25 + 30 + 25 = $80
B) This is the formula for variance is shown in figure :
So, we can calculate the variance as follows:
.2*(125-80)^2+.3*(100-80)^2+.5*(50-80)^2=975
C) A risk-neutral person would pay $80 or less to play the lottery.
To learn more about probability click here:
brainly.com/question/14210034
#SPJ4
Answer:
Here,
slope (m)=3
y-intercept (c)= -5
Now,
The equation of the line;
or,y=mx+c
or,y=3x-5
or,0=3x-y-5...is the required equation.