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Sergio039 [100]
3 years ago
13

A lock has four dials. On each dial are the digits 0 to 9 how many possible combinations are there

Mathematics
1 answer:
madam [21]3 years ago
7 0

Answer:

10,000

Step-by-step explanation:

The combination consists of four digits, hence 0000 to 9999. There at 10^4 or 10,000 possible combinations (but only one that works).

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You and three friends decide to go to the fair. The cost for parking is three dollars. Admission is 12 dollars per person. If yo
nika2105 [10]
Let the variable f represent the amount of money that each person can spend on food.

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Also, on the right side of the inequality, we know that you and your friends spend 3 dollars, because that is how much parking costs.  In addition to this, we have admission, which costs 12 dollars per person, and there are 4 people in your group. 12*4=48, which is the total cost of admission for your group.  Finally, you need to add the cost of food to this side of the inequality, which is the same for each person in your 4 person group.  This can be represented by the expression 4f.

So, if we write this inequality, it would be:

155≤ 3 + 48 + 4f

If we simplify the right side of the inequality, by combining like terms, we get the simplified inequality:
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To further simplify this inequality, we must keep all of the integers on the left side, in attempt to get the variable alone on the right side.  To do this, we must subtract 51 from both sides of the inequality, to get:

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26 ≤ f

This means that you and each of your friends can only spend 26 dollars each on food.
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