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3 years ago

How to find the altitude Of A Trapezoid Without Knowing The Area

Mathematics

1 answer:

Rudik [331]3 years ago

3 0

A=1/2 (b1+b 2)(h) is the area of a trapezoid

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Mike wants to make tarts. To make tarts, he needs 2 1/5 cups of flour per batch of tarts. If mike has 11 cups of flour, then how

dusya [7]

Answer:

5 batches

Step-by-step explanation:

Each batch takes 2 1/5 = 11/5 cups of flour. That is 1/5 of 11 cups of flour.

If Mike has 11 cups of flour and uses 1/5 of that amount for each batch, he can make 5 batches.

4 0

3 years ago

PLEASE HELP 25 POINTSSS

Crank

Use photomath it'll solve it for you easily and it's always correct work for any kind of math

4 0

3 years ago

Plz help i have school in 30 mins

wariber [46]

Answer: cant seee itt so .. blury srry

Step-by-step explanation:

8 0

3 years ago

The voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has

ANTONII [103]

Answer:

The voltage in exponential form would be $(\frac{3}{5})^3$ .

The original voltage in the circuit is $\frac{3}{5}$ of a volt.

Step-by-step explanation:

Let x represent the original voltage.

We have been given that the voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has been reduced 3 times.

The original voltage multiplied by itself for 3 times would be $x\cdot x\cdot x=x^3$ .

Now, we will equate $x^3$ with 27/125 as:

$x^3=\frac{27}{125}$

We know that 27 is cube of 3 and 125 is cube of 5, so we can represent our equation as:

$x^3=\frac{3^3}{5^3}$

$x^3=(\frac{3}{5})^3$

Therefore, the voltage in exponential form would be $(\frac{3}{5})^3$

Now, we will take cube root of both sides to find original voltage in the circuit as:

$\sqrt[3]{x^3} =\sqrt[3]{(\frac{3}{5})^3}$

Using property $\sqrt[n]{a^n} =a$ , we will get:

$x =\frac{3}{5}$

Therefore, the original voltage in the circuit is $\frac{3}{5}$ of a volt.

6 0

4 years ago

Consider the following.3x + 3y = 8(a) Find y' by implicit differentiation.(b) Solve the equation explicitly for y and differenti

ludmilkaskok [199]

Answer:

a.y'=-1

b.y'=-1

c.Yes

Step-by-step explanation:

We are given that consider a function

$3x+3y=8$

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a. $3x+3y=8$

Differentiate w.r.t x then we get

$3+3\frac{dy}{dx}=0$

$3\frac{dy}{dx}=-3$

$\frac{dy}[dx}=\frac{-3}{3}=-1$

$\frac{dy}{dx}=y'=-1$

b. $3x+3y=8$

$3y=8-3x$

$y=\frac{8-3x}{3}$

Differentiate w.r.t x then we get

$\frac{dy}{dx}=\frac{-3}{3}=-1$

$\frac{dy}{dx}=y'=-1$

When we substituting the value of y obtained from part b into a solution of part a then we get

$y'=-1$

Hence, solutions are consistent.

8 0

3 years ago