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2 years ago

How do you do two x to the second plus nine x minus five equal zero

Mathematics

1 answer:

Amanda [17]2 years ago

8 0

Answer: are you asking what is the answer?

Step-by-step explanation:

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A new car is purchased for $17,000 and over time its value depreciates by one half every 3 years. What is the value of the car 1

Jet001 [13]

Answer:

The answer is "$238".

Step-by-step explanation:

Current worth $= \$ 17,000$

depreciates by $\frac{1}{2}$ in 3 years.

time= 19 years

depreciates rate=?

Using formula:

$\to \text{Worth= Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}$

$\to A_t=A_0(1-\frac{r}{100})^t$

calculates depreciate value in 3 year $= \frac{1}{2} \times 17,000$

$= 8,500$

so,

$A_t=8,500\\\\A_0=17,000\\\\t=3\ years$

$\to A_t=A_0(1-\frac{r}{100})^t\\\\\to 8,500= 17,000(1-\frac{r}{100})^3\\\\\to \frac{8,500}{17,000}= (1-\frac{r}{100})^3\\\\\to \frac{1}{2}= (1-\frac{r}{100})^3\\\\\to (\frac{1}{2})^{\frac{1}{3}}= (1-\frac{r}{100})\\\\\to 0.793700526 = (1-\frac{r}{100})\\\\\to \frac{r}{100} = (1-0.793700526)\\\\\to \frac{r}{100} = (1-0.8)\\\\\to r= 0.2 \times 100 \\\\\to r= 20 \%$

depreciates rate= 20%

$\to \text{Worth= Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}$

$= \$ 17,000 (1- \frac{20}{100})^{19}\\\\= \$ 17,000 (1-0.2)^{19}\\\\= \$ 17,000 (0.8)^{19}\\\\= \$ 17,000 \times 0.014\\\\= \$ 238$

4 0

2 years ago

Read 2 more answers

During a 12-hour period, the temperature in a city dropped from a high of 60°F to a low of -25°F. What was the range of the temp

dexar [7]

29 because I got it right just kbow

4 0

3 years ago

A reflection across the x-axis keeps the x-coordinate the same but flips the y-coordinate. What do you think a reflection across

Studentka2010 [4]

Answer: A reflection across the x-axis keeps the x-coordinates the same but flips the signs of the y-coordinates. So, it should be the opposite for a reflection across the y-axis. The y-coordinates remain the same, but the signs of the x-coordinates change.

Step-by-step explanation

I copy and pasted the answer

8 0

2 years ago

Solve the formula d = rt for t. A. t = rd B. t = d – r C. t = D. t =

tekilochka [14]

$rt=d\qquad\text{divide both sides by}\ r\neq0\\\\\dfrac{rt}{r}=\dfrac{d}{r}\\\\\boxed{t=\dfrac{d}{r}}$