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kap26 [50]
3 years ago
12

Anybody know the answer?

Mathematics
1 answer:
ozzi3 years ago
7 0
6 cm i thinking not i’m sorry!!
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I believe the answer is 5x
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What is the slope of line LM given L(9, -2) and M(3, -5)?
jasenka [17]

Answer:

1/2

Step-by-step explanation:

(y2-y1)/(x2-x1) is the equation for finding slope with two given points

-5-(-2) over 3-9 equals

-3/-6=-1/-2=1/2

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On a coordinate graph,which of the following is true of Quadrant 3?
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D. The x and y values are both negative

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Guys I need help, this is so important for my grade
Dmitrij [34]

Answer:

For Part C) use numbers 1 2 3 4.

Step-by-step explanation:

8 0
3 years ago
Please answer this question too! :D
Artyom0805 [142]

Answer:

A

Step-by-step explanation:

We can find the surface area of the object by adding the surface areas of each part. We have many rectangle faces to count and two triangular faces. Each has a formula for the area. We will find the area of each and then add them all together.

Triangle - 0.5 *b*h

Rectangle - b*h

<u>Triangles</u>

There are two triangles on either side. The height is 1.5. The base is 1.8.

0.5(1.5)(1.8)=1.35 meters squared

Since there are two, we will add 1.35+1.35 in our final calculation.

<u>Rectangles</u>

We will start by calculating the largest rectangle on the side. It has height of 4 and a base of 2.5 (shown above left).

4(2.5)=10

Since there are two (one we can see and one we can't), we will add 10+10 in our final calculation.

Next we calculate the top and bottom. The height is 3 and the base is 2.5 on top. But the bottom sticks out more and adds 1.8 to its base.

Top - 3(2.5)=7.5

Bottom-3(2.5+1.8)=12.9

Finally, we will calculate the front side and back(not visible) as well as the slant up front. The back side has height 4 and base 3. The front side has base 3 and height 4-1.5=2.5. The slant has base 2.3 and height 3.

Back - 4(3)=12

Front- 3(2.5)=7.5

Slant - 3(2.3)=6.9

We add all together for the total surface area: 1.35+1.35+10+10+7.5+12.9+12+7.5+6.9=69.5 meters squared.

5 0
3 years ago
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