Answer:
94 pizzas will be sold
Step-by-step explanation:
We have to use the equation and replace 15 with x.
x=15
y=3.4x + 43
y=3.4(15) + 43
y=51 + 43
y=94
(15,94)
There will be 94 pizzas sold nightly if 15 coupons were issued.
There are 9 marbles in the bag. We pick 2 without replacement and get a probability of 1/6.
Each draw of a marble has a probability associated with it. Multiplying these gives 1/6 so let us assume the probabilities are (1/3) and (1/2).
In order for the first draw to have a probability of 1/3 we need to draw a color that has (1/3)(9)=3 marbles. So let's say there are 3 red marbles. The P(a red marble is drawn) = 1/3.
Now that a marble has been drawn there are 8 marbles left. In order for the second draw to have a probability of 1/2 we must draw a color that has (1/2)(8) = 4 marbles. So let's say there are 4 blue marbles out of the 8.
Since there are 9 marbles to start and we have 3 red marbles and 4 blue marbles, the remaining 2 marbles must be a different color. Let us say they are green.
The problem is: There are 3 red marbles, 4 blue marbles and 2 green marbles in a jar. A marble is picked at random, it's color is noted and the marble is not replaced. A second marble is drawn at random and its color noted. What is the probability that the first marble is red and the second blue?
Answer:
D
Step-by-step explanation:
Assuming the figure PQRS is a parallelogram, then opposite sides are congruent, that is
PQ = RS ← substitute in values
6x + 2 = 12 + x ( subtract x from both sides )
5x + 2 = 12 ( subtract 2 from both sides )
5x = 10 ( divide both sides by 5 )
x = 2 → D
Area of rectangle: 7 x 10 = 70 in2
Area of semicircle: (r^2*π)/2 = 3.5^2 * π /2 = 6.125*<span>π
</span>
=> Total area = 70 + 6.125*<span>π = 70 + approx 19.24 = approx. 89.24 in2</span>
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The closest number here is 89 in2, so the answer is 89 in2.
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