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alekssr [168]
2 years ago
5

for a set of 3 consecutive odd intergers, 3times the largest interger is 7 less than twice the sum of the other 2 intergers. wha

t is the largest interger in the set
Mathematics
2 answers:
kirill115 [55]2 years ago
5 0
ZnanMmznMmmzmamamansnsnsn
goldfiish [28.3K]2 years ago
3 0

For a set of 3 consecutive odd integers,

n, (n+2), (n+4)

3 times the largest integer is 7 less than twice the sum of the other 2 integers.

3(n+4) = 2(n + n+2) - 7

3n + 12 = 2(2n + 2) - 7

3n + 12 = 4n + 4 - 7

3n + 12 = 4n - 3

12 + 3 = 4n - 3n

 

15 = n is the 1st integer

:

What is the largest integer in the set  

15 + 4 = 19 is the largest integer

:

:

See if that checks out in the statement

"3 times the largest integer is 7 less than twice the sum of the other 2 integers. "

3(19) = 2(15 + 17) - 7

57 = 2(32) - 7

mark brailiest

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Fifteen times the square of a non-zero number is equal to 20 times number.What is the number? Its not 4/3
e-lub [12.9K]
The number is (2√3) / 3

To find the missing number, convert what it says in words to an equation:
15 {x}^{2}  = 20x
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4 0
3 years ago
There is a cereal box and the dimensions are 10 inches tall, 3 inches wide and 7 inches long. If you were to fill the box with c
JulsSmile [24]

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Since it costs $.03 per cubic inch, multiply this cost by the volume to get the total cost to fill the box.

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6 0
2 years ago
X^2+11x+30 ?????????????????????
kari74 [83]

Solution:

X^2+11x+30

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4 0
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