for a set of 3 consecutive odd intergers, 3times the largest interger is 7 less than twice the sum of the other 2 intergers. wha
t is the largest interger in the set
2 answers:
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For a set of 3 consecutive odd integers,
n, (n+2), (n+4)
3 times the largest integer is 7 less than twice the sum of the other 2 integers.
3(n+4) = 2(n + n+2) - 7
3n + 12 = 2(2n + 2) - 7
3n + 12 = 4n + 4 - 7
3n + 12 = 4n - 3
12 + 3 = 4n - 3n
15 = n is the 1st integer
:
What is the largest integer in the set
15 + 4 = 19 is the largest integer
:
:
See if that checks out in the statement
"3 times the largest integer is 7 less than twice the sum of the other 2 integers. "
3(19) = 2(15 + 17) - 7
57 = 2(32) - 7
mark brailiest
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The Answer: (-b + 15) (15 - b)
Answer:
the answer would be b
Step-by-step explanation:
the other 2 have negatives and the 3rd option is whole so b