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3 years ago

Which point is on the line of the equation y-4 = -1/2 (x - 2) ?

Mathematics

1 answer:

Gennadij [26K]3 years ago

8 0

Answer:

4.0148 rounded to the nearest thousand is 0, but if you meant rounded to the nearest thousandth, it would be 4.015 because the 8 in the ten thousandth column would cause the 4 in the thousandth column to round up to 5.

Step-by-step explanation:

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What is the solution to the system of equations below?

Ymorist [56]

Answer:

6×+÷3=2+4×=6

3x 8x+6 =8×+y1×-2

6 0

3 years ago

Read 2 more answers

Please help me again this due midnight

pishuonlain [190]

Answer:

A) 0.5 g/cm³

Step-by-step explanation:

To find volume, you must multiply length × width × height

So it would be 3 × 2 × 4

3 × 2 × 4 = 24

Volume = 24

Plug in both numbers into the equation for Density

12 ÷ 24 = 0.5

The density will be 0.5 g/cm³

4 0

2 years ago

Find the length of the diameter of a sphere with a surface area of 452.39^2 ft.

mash [69]

surface area = 4*pi*r^2

using 3.14 for pi

452.39 = 4*3.14*r^2=

452.39=12.56* r^2

r^2 = 452.39/12.56 = 36.0

sqrt(36) = 6= r

diameter = 2r = 6*2= 12

diameter = 12 feet

4 0

3 years ago

HELP I WILL GIVE BRAINLIEST!!!

lys-0071 [83]

T= 250 + 45a.

Since the cost of the medicine costs $250, and there is $45 dollars per appointment then 45 a would represent the 45 dollars for every appointment she chooses to have.

Hope this helps and have a nice day.

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7 0

3 years ago

As a result of medical examination, one of the tests revealed a serious illness in a person. This test has a high precision of 9

Elina [12.6K]

Answer:

0.0098

Step-by-step explanation:

Given,

Probability of test is positive if the person has disease, P(T/D)=0.99

Probability of test is negative if the person has disease,

P(T'/D) = 1-0.99 = 0.01

Probability of test is negative if the person hasn't disease, P(T'/D')= 0.99

Probability of test is positive if the person hasn't disease,

P(T/D') = 1 - 0.99 = 0.01

Probability of occurrence of disease, P(D) = 0.0001

Probability of not occurrence of disease,

P(D) = 1 - 0.0001 = 0.9999

Probability that test will be positive either disease is present or not,

P(T) = P(T/D).P(D)+P(T/D').P(D')

=0.99 x 0.0001 + 0.01 x 0.9999

= 0.000099 + 0.009999

= 0.010098

So, the probability that the person will have disease if the test is positive,

$P(D/T)\ =\ \dfrac{P(T/D).P(D)}{P(T)}$

$=\ \dfrac{0.99\times 0.0001}{0.010098}$

= 0.0098

So, the required probability will be 0.0098.

8 0

3 years ago