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3 years ago

FIND X ( SOMEONE PLEASE HELP MY EXAM IS ENDING :((( )

Mathematics

1 answer:

tatiyna3 years ago

8 0

Answer:

53 degrees

Step-by-step explanation:

to start the 11 + 3x is going to equal the 170 then take the two numbers and solve for x

11 + 3x = 170

minus 11 from both sides

3x = 159

divide by 3 on both sides

x = 53 degrees

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Brrunno [24]

Answer:

i) 7x + 8 = -90

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3 0

3 years ago

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What's the number when the quotient of a number and -7 decreased by 2 is 10?

dsp73

Let's read through this and make an equation:
? ("number")
? / -7 ("quotient of a number and -7")
(? / -7) - 2 ("decreased by 2")
(? / -7) - 2 = 10 ("is 10")

Now we can solve:
(? / -7) - 2 = 10
? / -7 = 12
? = -84

The number is -84

3 0

3 years ago

‼️‼️Help anyone ‼️‼️‼️

Debora [2.8K]

Method 1
You can use The equilateral triangle (look at the picture)
$\dfrac{a\sqrt3}{2}=1\ \ \ \cdot2\\\\a\sqrt3=2\ \ \ |\cdot\sqrt3\\\\3a=2\sqrt3\ \ \ |:3\\\\a=\dfrac{2\sqrt3}{3}\\\\\boxed{|AC|=\dfrac{2\sqrt3}{3}}$

Method 2
You can use the trigonometric function
$\sin60^o=\dfrac{1}{|AC|}\\\\\sin60^o=\dfrac{\sqrt3}{2}\\\\\dfrac{1}{|AC|}=\dfrac{\sqrt3}{2}\ \ \ |\cross\ multiply\\\\|AC|\sqrt3=2\ \ \ |\cdot\sqrt3\\\\3|AC|=2\sqrt3\ \ \ \ |:3\\\\\boxed{|AC|=\dfrac{2\sqrt3}{3}}$

4 0

3 years ago