Answer:
The number of cheese pizza sold is 200 cheese pizzas
The number of sausage pizza sold is 80 sausage pizzas
The number of pepperoni pizza sold is 120 pepperoni pizzas
Step-by-step explanation:
The price at which the pepperoni pizza was sold is $14
The price at which the sausage pizza was sold is $11
price at which the cheese pizza was sold is $10
The total number of pizzas sold = 400
The total amount made = $4560
The number of cheese pizza sold = 80 + the number of pepperoni pizzas
Let the number of cheese pizza sold = C
The number of sausage pizza sold = S
The number of pepperoni pizza sold = P
We have;
C + S + P = 400..........................(1)
C = 80 + P...................................(2)
10·C + 11·S + 14·P = $4560.......(3)
Substituting the value for C from equation (2) in equation (1), we get;
C + S + P = 400 = 80 + P + S + P = 400
2·P + S = 400 - 80 = 320
∴ S = 320 - 2·P..........................(4)
Substituting the value for C from equation (2) and the value for S from equation (4) into equation (3), we get;
10·C + 11·S + 14·P = $4560
10·(80 + P) + 11·(320 - 2·P) + 14·P = 4560
800 + 10·P + 3,520 - 22·P + 14·P = 4560
4,320 + 2·P = 4560
2·P = 4560 - 4,320 = 240
P = 240/2 = 120
P = 120
C = 80 + P = 80 + 120 = 200
C = 200
S = 320 - 2·P = 320 - 2×120 = 320 - 240 = 80
S = 80
Therefore;
The number of cheese pizza sold = C = 200
The number of sausage pizza sold = S = 80
The number of pepperoni pizza sold = P = 120.
