3 years ago

Given the following sequence, find the 14th term: 3, 1, –1, –3, –5, . . .

2 answers:

7 0

3, 1, -1, -3, -5
-2 -2 -2 -2

a(n) = a₁ + d(n - 1)
a(n) = 3 - 2(n - 1)
a(n) = 3 - 2(n) + 2(1)
a(n) = 3 - 2n + 2
a(n) = -2n + 3 + 2
a(n) = -2n + 5
a₁₄ = -2(14) + 5
a₁₄ = -28 + 5
a₁₄ = -23

The answer is C.

katrin2010 [14]3 years ago

6 0

C.-23 Just subtract two every time until you get to the 14 th number

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