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laila [671]
4 years ago
13

Given the following sequence, find the 14th term: 3, 1, –1, –3, –5, . . .

Mathematics
2 answers:
AVprozaik [17]4 years ago
7 0
3, 1, -1, -3, -5
 -2  -2  -2  -2

a(n) = a₁ + d(n - 1)
a(n) = 3 - 2(n - 1)
a(n) = 3 - 2(n) + 2(1)
a(n) = 3 - 2n + 2
a(n) = -2n + 3 + 2
a(n) = -2n + 5
   a₁₄ = -2(14) + 5
   a₁₄ = -28 + 5
   a₁₄ = -23

The answer is C.
katrin2010 [14]4 years ago
6 0
C.-23 Just subtract two every time until you get to the 14 th number 
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