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3 years ago

Solve for x. 5(x – 10) = 30 – 15x

2 answers:

6 0

If you want to solve for x, here's the answer: 5x-50 = 30-15x, 20x = 80, x = 4, so we conclude x is equal to 4. Hope this helped! Brainliest is always appreciated.

SIZIF [17.4K]3 years ago

3 0

Hey!

The first step to solving this problem would be to distribute the parenthesis. We do this so that we can get rid of the parenthesis.

Original Equation :
5 ( x - 10 ) = 30 - 15x

New Equation {Changed by Distribution} :
5x - 50 = 30 - 15x

The next step would be to 50 to both sides. The reason we do that is to get rid of the 50 that is on the left side of the equation.

Old Equation :
5x - 50 = 30 - 15x

New Equation {Changed by Adding 50 to Both Sides} :
5x = 80 - 15x

And now we would add 15x to both sides to get rid of the -15x on the right side of the equation.

Old Equation :
5x = 80 - 15x

New Equation {Changed by Adding 15x to Both Sides} :
20x = 80

Now we divide both sides by 20 to get x on it's own.

Old Equation :
20x = 80

New Equation {Changed by Dividing Both Sides by 20} :
$\frac{20x}{20}$ = $\frac{80}{20}$

Finally, all we have to do is solve to find x.

Old Equation :
$\frac{20x}{20}$ = $\frac{80}{20}$

Solution {Old Equation Solved} :
x = 4

So, in the equation 5 ( x – 10 ) = 30 – 15x, x = 4.

Hope this helps!

- Lindsey Frazier ♥

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2 years ago

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vaieri [72.5K]

Answer:

1st Option;

j = 4.5

k = 2

Step-by-step explanation:

Let's solve for "j" first:

=> We know that by the definition of midpoint segment theorem we can say;

3j = 5j - 9

0 = 5j - 3j - 9

0 = 2j - 9

0 + 9 = 2j

9 = 2j

9/2 = j

4.5 = j

=> Now that we have j-value we use the same method to solve for k-value;

6k = k + 10

6k - k = 10

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k = 10/5

k = 2

Therefore;

j = 4.5

k = 2

So the first option would be correct!

Hope this helps!

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3 years ago

0.01x - 0.3y = 1

dusya [7]

Answer:

x-30y=100 and 10y=x-20

Step-by-step explanation:

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Suppose an airline accepted 12 reservations for a commuter plane with 10seats. They know that 7 reservations went to regular com

kvv77 [185]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

7 persons will show up for sure, hence there is not any kind of probability here.

The other 5 persons have 50% chance to show up.

The flight will be overbooked, if either 4 will come or 5 will come.

From the total 5 persons, 4 can be chosen in $^5C_4 = 5$ ways.

The probability that any four among the 5 will come is $5\times(\frac{50}{100} )^{5} = 5\times(\frac{1}{2} )^{5} = \frac{5}{32}$ .

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(b)

The probability that there will be exactly 10 passengers on the flight is $^5C_3\times (\frac{1}{2} )^5 = \frac{20}{2} \times\frac{1}{32} = \frac{10}{32} = \frac{5}{16}$ .