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liberstina [14]

2 years ago

5

Is the function described by the points in this table linear or nonlinear?

1 answer:

vazorg [7]2 years ago

3 0

Answer:B)NONLINEAR

I just took the test and got it right

k12 too?

please mark brainliest answer

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What are the factors in the expression (a+b)12

BlackZzzverrR [31]

Solution:

1) Distribute
12a+12b

Done!

7 0

3 years ago

Help asap giving branlist!!

sergiy2304 [10]

Answer:

option 3

Step-by-step explanation:

x = 2 is a vertical line with an x-intercept of (2, 0) so the answer is Option 3.

3 0

2 years ago

Read 2 more answers

Sandra knows the Pythagorean identity sin 2 ⁡ θ + cos 2 ⁡ θ = 1 . If she is told that 0 ≤ θ ≤ π 2 and cos ⁡ θ = 5 12, what will

slavikrds [6]

Answer:

$\text{tan}(\theta)=\frac{\sqrt{119}}{5}$

Step-by-step explanation:

We have been given that Sandra knows the Pythagorean identity $\text{sin}^2(\theta)+\text{cos}^2(\theta)=1$ . She is told that $0\leq \theta\leq \frac{\pi}{2}$ and $\text{cos}(\theta)=\frac{5}{12}$ .

First of all, we will find value of sine theta using the given identity.

$\text{sin}^2(\theta)+\text{cos}^2(\theta)=1$

$\text{sin}^2(\theta)+(\frac{5}{12})^2=1$

$\text{sin}^2(\theta)+\frac{25}{144}=1$

$\text{sin}^2(\theta)+\frac{25}{144}-\frac{25}{144}=1-\frac{25}{144}$

$\text{sin}^2(\theta)=\frac{144-25}{144}$

$\text{sin}^2(\theta)=\frac{119}{144}$

$\text{sin}(\theta)=\sqrt{\frac{119}{144}}$

$\text{sin}(\theta)=\frac{\sqrt{119}}{12}$

$\text{tan}(\theta)=\frac{\text{sin}(\theta)}{\text{cos}(\theta)}$

$\text{tan}(\theta)=\frac{\frac{\sqrt{119}}{12}}{\frac{5}{12}}$

$\text{tan}(\theta)=\frac{\sqrt{119}*12}{5*12}=\frac{\sqrt{119}}{5}$

Therefore, $\text{tan}(\theta)=\frac{\sqrt{119}}{5}$ .

5 0

2 years ago

Determine the current through each of the LEDs in the circuits below. Which LED will be

Anika [276]

a. $I = 6. 1$ × $10^-4$ A

b. $I = 2. 6$ × $10^-3$ A

c. $I = 0. 04$ A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

$I = \frac{12}{19700}$

$I = 6. 1$ × $10^-4$ A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

$I = \frac{12}{4700}$

$I = 2. 6$ × $10^-3$ A

C. V= 12V

1/R = $\frac{1}{750} + \frac{1}{1200} + \frac{1}{950 }$ = $3. 22$ × $10^-3$

R = $\frac{1}{3. 22 * 10 ^-3}$ = 310. 56 Ω

$I = \frac{12}{310. 56}$

$I = 0. 04$ A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

#SPJ1

8 0

1 year ago

It costs the Quality Company $0.14 per mile to run its van. On Monday the van traveled 87.6 miles. How much did it cost to run t

Sveta_85 [38]

A would be your answer: $12.26

8 0

3 years ago