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pogonyaev
4 years ago
11

Solve the following equation for x to find the total number of people who became members of a social networking site for a certa

in month:
x = 0.8x + 72

How many people became members of the site that month?

112
288
360
432
Mathematics
2 answers:
zavuch27 [327]4 years ago
5 0

Answer:

360 people

Step-by-step explanation:

     x = 0.8x + 72           Subtract 0.8x on both sides

0.2x = 72                  Divide 0.2 on both sides

      x = 360

enot [183]4 years ago
4 0

Answer:

The Answer is C. 360

360 People Became Members of that website that Month

Hope This Helps!

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Help me please please​
Vera_Pavlovna [14]

Answer:

  3.88 nm

Step-by-step explanation:

The angle at Port Latta between the actual direction of travel and the destination at Lookout Point is 90° -75° = 15°. The sine function relates the angle, the side opposite, and the hypotenuse of a right triangle, so you have ...

  sin(15°) = (distance to Lookout Point)/(15 nm)

Solving for the desired distance, we have ...

  distance to Lookout Point = (15 nm)sin(15°) = 3.88 nm

The yacht is 3.88 nautical miles from Lookout Point.

3 0
3 years ago
Which expressions represent rational numbers? select all the apply. startroot 100 endroot startroot 100 endroot 13.5 startroot 8
zlopas [31]

The expressions are irrational 1/3 + √216 and √64+ √353 and the expressions √100 × √100, 13.5 + √81, √9 + √729, and 1/5 + 2.5 are rational number.

<h3>What is a rational number?</h3>

If the value of a numerical expression is terminating then they are the rational number then they are called the rational number and if the value of a numerical expression is non-terminating then they are called an irrational number.

1.  √100 × √100

→ √100 × √100

→ 10 × 10 = 100

This is a rational number.

2.  13.5 + √81

→ 13.5 + √81

→ 13.5 + 9 = 22.5

This is a rational number.

3.  √9 + √729

→ √9 + √729

→ 3 + 27 = 30

This is a rational number.

4.  √64+ √353

→ √64 + √353

→ 8 + √353

This is an irrational number.

5.  1/3 + √216

→ 1/3 + √216

→ 1/3 + √216

This is an irrational number.

6.  1/5 + 2.5

→ 1/5 + 2.5

→ 0.2 + 2.5 = 2.7

This is a rational number.

More about the rational number link is given below.

brainly.com/question/9466779

7 0
3 years ago
(ASAP) Billie &amp; Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen ye
jeka94

Answer:

Billie's age = x = 17 years

Tony's age = y = 31 years

Step-by-step explanation:

Let

Billie's age = x

Tony's age = y

Twice Billie’s age decreased by 3 is Tony’s age.

y = 2x - 3..... Equation 1

Tony is fourteen years older than Billie.

x = y - 14

We substitute y - 14 for x in Equation 1

y = 2x - 3..... Equation 1

y = 2(y - 14) - 3

y = 2y - 28 - 3

y - 2y = -28 - 3

-y = -31

y = 31 years

Solving for x

x = y - 14

x = 31 - 14

x = 17 years.

Therefore:

Billie's age = x = 17 years

Tony's age = y = 31 years

4 0
3 years ago
Read 2 more answers
(08.02)a pair of equations is shown below. 3x − y = 9 y = −2x + 11 if the two equations are graphed, at what point do the lines
mixas84 [53]
3x - y = 9
y = -2x + 11

3x - (-2x + 11) = 9
3x + 2x - 11 = 9
3x + 2x = 9 + 11
5x = 20
x = 20/5
x = 4

y = -2x + 11
y = -2(4) + 11
y = -8 + 11
y = 3

solution (where the lines intersect) is (4,3)
8 0
4 years ago
Read 2 more answers
Given that tan θ ≈ 1.072, where 0 &lt; θ &lt; , 2 π find the values of sin θ and cos θ.
anygoal [31]

Answer:

The answer to your question is

sin Ф = 0.731 and sinФ = -0.731; cos Ф 0.682 and cos Ф = -0.682

Step-by-step explanation:

tan Ф = 1.072,  0 < Ф < 2 π,   tan Ф is positive, find the solution in the first and third quadrangle.

- tan Ф = opposite side / adjacent side

- 1.072 / 1 = opposite side / adjacent side

- opposite side = 1.072 and adjacent side = 1

  Calculate hypotenuse

  c² = a² + b²

  c² = 1.072² + 1²

  c² = 2.149

  hypotenuse = c = 1.466

First quadrangle

  sin Ф = 1.072 / 1.466 = 0.731

  cos Ф = 1 / 1.466 = 0.682

Third quadrangle

  sin Ф = -1.072 / 1.466 = -0.731

  cos Ф = -1 / 1.466 = -0.682

5 0
3 years ago
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