Given:
The first two terms in an arithmetic progression are -2 and 5.
The last term in the progression is the only number in the progression that is greater than 200.
To find:
The sum of all the terms in the progression.
Solution:
We have,
First term : 
Common difference : 
nth term of an A.P. is
where, a is first term and d is common difference.
According to the equation, 
.
Divide both sides by 7.
Add 1 on both sides.
So, least possible integer value is 30. It means, A.P. has 30 term.
Sum of n terms of an A.P. is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Substituting n=30, a=-2 and d=7, we get
![S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D%5Cdfrac%7B30%7D%7B2%7D%5B2%28-2%29%2B%2830-1%297%5D)
![S_{30}=15[-4+(29)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B%2829%297%5D)
![S_{30}=15[-4+203]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B203%5D)
Therefore, the sum of all the terms in the progression is 2985.
Answer:
x^2 y ^4 ∛ [x^2 y ^2 ] is the answer that I got
Step-by-step explanation:
<h3>
Answer: D. 5 blinks</h3>
=========================================================
Explanation:
First we'll need to find out how long it takes for the ball to go from the pitcher to the batter.
It needs to travel 60.5 feet and does so at a speed of 121 ft/sec
distance = speed*time
time = distance/speed
time = (60.5 ft)/(121 ft per sec)
time = 0.5 seconds
In half a second, the ball is from the pitcher to the batter.
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An eye blink is 0.1 second which means we can form this equation
0.1 second = 1 blink
We multiply both sides by 5 to get the "0.1 second" to turn into "0.5 seconds".
So,
0.1 second = 1 blink
5*(0.1 second) = 5*(1 blink)
0.5 seconds = <u>5 blinks</u> which points us to choice D.
25.2 / 7.8 = ~ 3.23 hope that helps
Answer:
2x+15y=2960
Step-by-step explanation:
