<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:
y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5
The formula to be used in the proceeding steps is a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting, a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5) =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope
y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
A=p (1+r/k)^kt
A=500×(1+0.02÷3)^(3×4)
A=541.50
Answer:
14 mm squared is the area
Step-by-step explanation:
Answer:
Step-by-step explanation:
Step 1:-
using logarithmic formula 
so given 
now simplify
= 
<u>Answer:</u>-
![log(x^{3}y^{2})= [tex]3 log x+2 log y](https://tex.z-dn.net/?f=log%28x%5E%7B3%7Dy%5E%7B2%7D%29%3D%20%5Btex%5D3%20log%20x%2B2%20log%20y)
Since it forms a "right triangle" we can apply trigonometry.
sin x = oppo/hyp
sin x = 13/20
x = sin^-1(13/20)
x = sin^-1(0.65)
x = 40.5
rounded to nearest degree
x = 41 degrees
Hope this helps! :)
