Answer:
60%
Step-by-step explanation:
You can solve this problem by setting up a system of equations.
Let's say that the number of tickets bought by students in the first year is x, and the number bought by continuing students is y. From there, you can set it up like this:
0.4x+0.2y=160
x+y=500
Now, you can multiply the first equation by 5 on both sides to get:
2x+y=800
Subtracting the second equation from the first equation now yields:
x=300
y=200
Since 300 of the 500 tickets bought were from the first year students, and 300/500 is 0.6, 60% of the students who bought the ticket were first year students. Hope this helps!
Answer:
B) -5, 5, -7, 7
Step-by-step explanation:
3x² - bx + 2
factor:
(3x - 2 )(x - 1) = 3x² - (5)x + 2 so 5 does work
(3x - 1 )(x - 2) = 3x² - (7)x + 2 so 7 does work
(3x + 2 )(x + 1) = 3x² + 5x +2 = 3x² - (-5)x + 2 so -5 does work
(3x + 1 )(x + 2) = 3x² + 7x + 2 = 3x² - (-7)x + 2 so -7 does work
You know that you have the Opposite side and the Adjacent side. therefore you would use Tangent (T= O/A)
because you are finding the angle you would go Tan^-1(12÷20) =31°
it is 12÷20 because O/A and the 12 is the opposite side therefore It would be O and 20 is the adjacent side therefore equaling 20 so O/A = 12/20
Your answer is 31°
Answer:
Step-by-step explanation:
x + 159 = 180
x = 21
X=3
Y=-8
Z= 1
hope that helps
