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Softa [21]
2 years ago
5

What is the volume of a sphere with a diameter of 7.9 ft

Mathematics
1 answer:
vovangra [49]2 years ago
5 0

Answer:

V ≈ 258 ft³

Step-by-step explanation:

I given the diameter d= 7.9 ft so the radius is r = d/2 = 7.9/2  ft

Volume of a sphere is

V = (4/3) π·r³ = (4/3) · π · (7.9/2)³ = 258.1546167 ft³

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MAX is equiangular If m
Evgen [1.6K]
What’s the question?
3 0
3 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
Bond [772]

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }

.

.

.

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }

.

.

.

Following the pattern, we can see that for f^{n}(x),

f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} }  \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}

This applies for n ≥ 1, Expressing f(x) in summation, we have

\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}

Combining ln2 with the rest of series, we have

f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0
2 years ago
h(n)=-13nh(n)=−13nh, left parenthesis, n, right parenthesis, equals, minus, 13, n Complete the recursive formula of h(n)h(n)h, l
mr Goodwill [35]

Answer:

h(1)=-13

h(n)=h(n-1)-13, n\geq 2

Step-by-step explanation:

We are given that

h(n)=-13n

We have to find the recursive formula of h(n).

Substitute n=1

h(1)=-13

n=2

h(2)=-13-13=-26=h(1)-13

n=3

h(3)=-13(3)=-39=-26-13=h(2)-13

h(4)=-13(4)=-52=-39-13=h(3)-13

:

:

:

h(n)=h(n-1)-13

Therefore, the recursive formula is given by

h(1)=-13

h(n)=h(n-1)-13, n\geq 2

5 0
3 years ago
18. Mabel gave Margo a bag containing red, white, and
Sedbober [7]
So if the bag contains half as many red marbles as blue ones, and there are 8 reds then there are 16 blues. 16 + 8= 24 if you want there to be 1/4 white marbles add 6. 6/30 is 1/4.

So the answer comes out to be 30 marbles in the bag
4 0
3 years ago
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How I divided a hexagon into 3 equal parts ?
Furkat [3]
It splits into 6 easerly so just make each part double walls as the pic shows

3 0
3 years ago
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