Cables are forming 3 right angled triangles the pole being the shared height of them;
(height) b= 12yd
(base) a= 9yd
(hypotenuse) c= ?
Need to find the long side (hypotenuse);
a^2 + b^2 = c^2
12^2 + 9^2 = 225
Take square root of 225 = 15
Then you have;
1x 12yd = 12
3x 9 yd = 27
3x 15yd = 45
Add them up = 84yd of cable needed
Here's how you solve this. So, x+y=2, right? Let's isolate x. x+y-y=2-y. x=2-y. NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y! 3x+2y=5. 3(2-y)+2y=5. (3*2)+(3*-y)+2y=5. 6+(-3y)+2y=5. 6+(-y)=5. 6+(-y)-6=5-6. -y=-1. -y/-1=-1/-1. y=1.
So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2. x+1=2. x+1-1=2-1. x=1. 1+1=2, so that works; let's check the other equation. 3(1)+2(1)=5. 3+2=5. 5=5. That's correct!
Answer: x=1, y=1
The slope would be -5
Hope this helps
Have a great day/night
5 and 7
5 + 7 = 12
5 x 7 = 35
