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2 years ago

What is the volume of a sphere with a diameter of 7.9 ft

Mathematics

1 answer:

vovangra [49]2 years ago

5 0

Answer:

V ≈ 258 ft³

Step-by-step explanation:

I given the diameter d= 7.9 ft so the radius is r = d/2 = 7.9/2 ft

Volume of a sphere is

V = (4/3) π·r³ = (4/3) · π · (7.9/2)³ = 258.1546167 ft³

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MAX is equiangular If m

Evgen [1.6K]

What’s the question?

3 0

3 years ago

Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

Bond [772]

Taylor series is $f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

$f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }$

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

$f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }$

Following the pattern, we can see that for $f^{n}(x)$ ,

$f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} } \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}$

This applies for n ≥ 1, Expressing f(x) in summation, we have

$\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}$

Combining ln2 with the rest of series, we have

$f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

Taylor series is $f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0

2 years ago

h(n)=-13nh(n)=−13nh, left parenthesis, n, right parenthesis, equals, minus, 13, n Complete the recursive formula of h(n)h(n)h, l

mr Goodwill [35]

Answer:

h(1)=-13

$h(n)=h(n-1)-13, n\geq 2$

Step-by-step explanation:

We are given that

$h(n)=-13n$

We have to find the recursive formula of h(n).

Substitute n=1

$h(1)=-13$

n=2

$h(2)=-13-13=-26=h(1)-13$

n=3

$h(3)=-13(3)=-39=-26-13=h(2)-13$

$h(4)=-13(4)=-52=-39-13=h(3)-13$

$h(n)=h(n-1)-13$

Therefore, the recursive formula is given by

h(1)=-13

$h(n)=h(n-1)-13, n\geq 2$

5 0

3 years ago

18. Mabel gave Margo a bag containing red, white, and

Sedbober [7]

So if the bag contains half as many red marbles as blue ones, and there are 8 reds then there are 16 blues. 16 + 8= 24 if you want there to be 1/4 white marbles add 6. 6/30 is 1/4.

So the answer comes out to be 30 marbles in the bag

4 0

3 years ago

Read 2 more answers

How I divided a hexagon into 3 equal parts ?

Furkat [3]

It splits into 6 easerly so just make each part double walls as the pic shows

3 0

3 years ago