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Softa [21]
2 years ago
5

What is the volume of a sphere with a diameter of 7.9 ft

Mathematics
1 answer:
vovangra [49]2 years ago
5 0

Answer:

V ≈ 258 ft³

Step-by-step explanation:

I given the diameter d= 7.9 ft so the radius is r = d/2 = 7.9/2  ft

Volume of a sphere is

V = (4/3) π·r³ = (4/3) · π · (7.9/2)³ = 258.1546167 ft³

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3 years ago
A kite ascends at a rate of 30 feet per minute. What is the elevation after 6.5 minutes
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7 0
3 years ago
Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a
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Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be representedh(t)=-16t^2+20t.

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?  

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}

\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}

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\text{Average rate of change}=\frac{2\cdot 6}{1}

\text{Average rate of change}=12

Therefore, Spot's average rate of ascent is 12 feet per second.

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Answer:

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Step-by-step explanation:

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